Got a doosie here, Angular acceleration, time and radius.

In summary, the problem focuses on finding the time of one rotation and the radial acceleration of an Earth satellite in a circular orbit with an orbital speed of 6200 m/s. The relevant equations are Ac= V^2/R, mAc=mg, and V= 2(pi)R/t. However, the person asking for help is unsure about the other variables, such as the radius of the earth and the effect of gravity. They also mention that one rotation is equivalent to 2(pi) radians. Further guidance is needed to solve the problem.
  • #1
GRice40
20
0

Homework Statement


An Earth satellite moves in a circular orbit with an orbital speed of 6200 m/s. Find the time of one rotation as well as the radial acceleration of the satellite in orbit.


Homework Equations


Ac= V^2/R
mAc=mg
V= 2(pi)R/t


The Attempt at a Solution



Ok, I've gone every which way I can with this problem. I don't know how to go about it. I've drawn an FBD and the only forces I can see acting on it are the weight of the satellite and the Ac. I don't know if there is supposed to be another variable that is assumed, like the radius of the earth, or if gravity acts upon the satellite at 9.8 m/s^2 like it would on earth...I'm pretty lost here. Any advice on how to start?
 
Physics news on Phys.org
  • #2
I believe the orbital speed is the tangential speed of the satellite.

What is one rotation? (quickly, go back to your unit circle!)
 
  • #3
One rotation is 2(pi) radians, iirc.
 
  • #4
I still don't know where to go from there, it seems like I need another variable somehow...
 
  • #5


I would recommend starting by identifying the known variables and equations that relate to the problem. In this case, we know the orbital speed of the satellite (6200 m/s) and we can use the equation V= 2(pi)R/t to relate it to the time of one rotation (t). We also know that the radial acceleration (Ac) can be calculated using the equation Ac= V^2/R.

Next, we can consider the forces acting on the satellite. As you mentioned, the only forces we need to consider are the weight of the satellite and the centripetal force (Ac). The weight of the satellite can be calculated using the equation mAc=mg, where m is the mass of the satellite and g is the acceleration due to gravity (which is 9.8 m/s^2 on Earth).

To find the time of one rotation, we can rearrange the equation V= 2(pi)R/t to solve for t. Then, we can plug in the given values for V and R to find the time. To find the radial acceleration, we can use the equation Ac= V^2/R and plug in the given values for V and R.

I hope this helps guide you in solving the problem. Remember to always start by identifying the known variables and equations, and then think about the forces at play. Good luck!
 

FAQ: Got a doosie here, Angular acceleration, time and radius.

What is angular acceleration?

Angular acceleration is the rate of change of angular velocity over time. It is a measure of how quickly an object's rotational speed is increasing or decreasing.

How is angular acceleration calculated?

Angular acceleration is calculated by dividing the change in angular velocity by the change in time. The unit of measurement for angular acceleration is radians per second squared (rad/s^2).

How does angular acceleration relate to linear acceleration?

Angular acceleration and linear acceleration are related through the radius of rotation. The formula is: linear acceleration = angular acceleration x radius of rotation.

What is the difference between angular acceleration and angular velocity?

Angular acceleration measures how much an object's angular velocity changes over time, while angular velocity measures the rate of change of an object's angular displacement over time. In simpler terms, angular acceleration is the change in rotational speed, while angular velocity is the rotational speed itself.

How does the radius of rotation affect angular acceleration?

The radius of rotation has a direct effect on angular acceleration. A larger radius will result in a smaller angular acceleration, while a smaller radius will result in a larger angular acceleration. This is because the same angular velocity is being spread over a larger or smaller distance, resulting in a change in rotational speed.

Back
Top