Graph of y=x^(1/3) and y= -2x^(1/2)

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In summary, the person is asking for help with sketching the graphs of y=x^(1/3) and y=-2x^(1/2). They mention that they are unsure of the proper procedure or technique for sketching these types of graphs. Another person suggests choosing specific x values and using the general shape of the functions to draw an approximation of the lines. They also offer a hint for the second graph, stating that it is a stretched and reflected version of y=x^(1/2).
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Michael_Light
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Homework Statement



What is the procedure or hints of sketching this type of graph (i.e. y=x^(1/3) and y= -2x^(1/2) )? I know how it looks like but i had no ideas what is the proper procedure or technique of sketching them. Please help...

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The Attempt at a Solution



I tried but i really don't know how to do...
 
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  • #2
choose some x values, for example 0,1, and -1, and then, since you know the general shape of the functions, draw an approximation of the lines.
 
  • #3
For the second one, presumably you know the shape of y = x^(1/2). Relative to this graph, the graph of -2x^(1/2) is stretched away from the x-axis by a factor of 2 and then reflected across the x-axis.
 

FAQ: Graph of y=x^(1/3) and y= -2x^(1/2)

What is the graph of y=x^(1/3) and y= -2x^(1/2)?

The graph of y=x^(1/3) and y= -2x^(1/2) is a curve that intersects at the origin (0,0) and extends outwards in both positive and negative directions. The curve for y=x^(1/3) is steeper and approaches the x-axis more quickly than the curve for y= -2x^(1/2), which is flatter and approaches the x-axis more gradually.

What are the key features of the graph of y=x^(1/3) and y= -2x^(1/2)?

The key features of the graph of y=x^(1/3) and y= -2x^(1/2) are the origin (0,0), the curves that intersect at the origin, and the direction and steepness of the curves as they extend outwards.

What is the domain and range of the graph of y=x^(1/3) and y= -2x^(1/2)?

The domain of the graph of y=x^(1/3) and y= -2x^(1/2) is all real numbers. The range for y=x^(1/3) is all real numbers, while the range for y= -2x^(1/2) is only positive real numbers.

What are the x-intercepts and y-intercepts of the graph of y=x^(1/3) and y= -2x^(1/2)?

The x-intercepts of the graph of y=x^(1/3) and y= -2x^(1/2) are at the origin (0,0). The y-intercept of y=x^(1/3) is also at the origin, while the y-intercept of y= -2x^(1/2) is not defined.

How do you determine the direction of the curves for y=x^(1/3) and y= -2x^(1/2)?

The direction of the curves for y=x^(1/3) and y= -2x^(1/2) can be determined by looking at the coefficients of the exponents. The coefficient for y=x^(1/3) is 1, which means the curve will point upwards as x increases. The coefficient for y= -2x^(1/2) is -2, which means the curve will point downwards as x increases.

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