- #1
latentcorpse
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I have a very simple question about the Dirac equation that I just cannot see the answer to.
In these notes:
http://www.damtp.cam.ac.uk/user/tong/qft/qft.pdf
In equation 4.115, I keep getting
[itex]u( \vec{p} ) = \begin{pmatrix} \sqrt{p \cdot \sigma} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \\ \sqrt{ p \cdot \bar{\sigma}} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \end{pmatrix} = \begin{pmatrix} \sqrt{E - p \sigma^3} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \\ \sqrt{E + p \sigma^3} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \end{pmatrix}[/itex]
So why does [itex]p^3 = p \sigma^3[/itex] or is there a typo?
I would have thought that since [itex]p^\mu = ( E,0,0,p)[/itex], we should get [itex]p^3=p[/itex], no?
Thanks for any help!
In these notes:
http://www.damtp.cam.ac.uk/user/tong/qft/qft.pdf
In equation 4.115, I keep getting
[itex]u( \vec{p} ) = \begin{pmatrix} \sqrt{p \cdot \sigma} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \\ \sqrt{ p \cdot \bar{\sigma}} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \end{pmatrix} = \begin{pmatrix} \sqrt{E - p \sigma^3} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \\ \sqrt{E + p \sigma^3} \begin{pmatrix} 1 \\ 0 \end{pmatrix} \end{pmatrix}[/itex]
So why does [itex]p^3 = p \sigma^3[/itex] or is there a typo?
I would have thought that since [itex]p^\mu = ( E,0,0,p)[/itex], we should get [itex]p^3=p[/itex], no?
Thanks for any help!