Help with Integration: θ/(θ+2) from x=0 to 1

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In summary, the conversation is about a statistical problem involving integration and the equation θ(θ+1)∫xθ(1-x)dx = θ/(θ+2). The person is seeking help or tips on how to solve this problem. An expert provides a more readable form of the equation and suggests using basic integration skills.
  • #1
bpschn01
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Hi,

I am told that:
θ(θ+1)∫xθ(1-x)dx = θ/(θ+2)
∫ from x=0 to 1
Would someone be so kind as to show me how, or give me some tips.

This is a small part of a solution for a statistical problem I'm trying to understand.
Thank you ...
 
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  • #2
(x^t)(1-x) = (x^t) - (x^(t+1))
You know how to integrate (x^t) , i suppose.
 
  • #3
bpschn01 said:
Hi,

I am told that:
θ(θ+1)∫xθ(1-x)dx = θ/(θ+2)
∫ from x=0 to 1
Would someone be so kind as to show me how, or give me some tips.

This is a small part of a solution for a statistical problem I'm trying to understand.
Thank you ...
In more readable form, and with θ replaced by t, the equation is
$$ t(t + 1) \int_0^1 x^t(1 - x)dx = \frac{t}{t + 2}$$
 
  • #4
Thanks JJacquelin! It's the simple stuff that gets me.
 

FAQ: Help with Integration: θ/(θ+2) from x=0 to 1

What is Integration?

Integration is a mathematical process used to find the area under a curve. It is used to calculate the total value of a quantity over a given interval.

What is θ/(θ+2)?

θ/(θ+2) is a mathematical expression that represents a function. In this expression, θ is the independent variable and (θ+2) is the dependent variable.

What does x=0 to 1 mean in the context of this problem?

In this problem, x=0 to 1 represents the interval over which we are finding the area under the curve. In other words, we are finding the area under the curve from x=0 to x=1.

How do you solve the integral θ/(θ+2) from x=0 to 1?

To solve this integral, we can use the substitution method. Let u = θ+2, then du = dθ. Substituting these values into the integral, we get ∫u/u du. This is equal to ∫1 du, which evaluates to u + C. Substituting back in for u, we get θ+2 + C. Evaluating this from x=0 to 1, we get (1+2+C) - (0+2+C) = 3-2 = 1.

What is the significance of solving this integral?

Solving this integral allows us to calculate the area under the curve of the function θ/(θ+2) over the interval from x=0 to x=1. This can be useful in various fields such as physics, engineering, and economics, where finding the total value of a quantity over a given interval is necessary.

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