Help with Stress Tensor: Local vs Other Observers

In summary, The conversation discusses the stress energy tensor and its components, specifically in relation to different observers and Lorentz transformations. The tensor itself is not invariant, but certain scalars formed from it can be.
  • #1
Jitu18
4
0
Well lately i have in mess for this. The problem is about the stress energy tensor. Well we know that
T_mn = r0 U^m U^n
where r0 is mass density and U is proper velocity. Ok now consider the local observer. For him except for U^0 other U^m will be jero. So for local observer.
T_00 = r0 c^2
other component of this tensor will be zero. Surely for other observer almost all the component maybe nonzero. And T_00 component for other observer will be
T_00 = r0 c^2 (dt/dTou)^2
here tou is proper time. And it will be greater than T_00 of local observer. So how can the T tensor remain invariant. Sure its trace can't be the same. For other observer T_00 it self is bigger let alone the other nonzero component. Please help me here. Its bugging me a lot. If u dnt understand something about my writing than tell me.
 
Physics news on Phys.org
  • #2
If you boost a 4-vector, the vector changes, but the scalar length is unchanged.
So it is with Tmn, the components change but scalars made from it do not.
 
  • #3
Yes i know it. But that's the problem. Local observer has only one nonzero component while other observer's same tensor have lot of nonzero component. some of those component may be bigger than the local observer's only componet. So will the scalar or length will be same? Other observer's T tensor's magnitude sure seems much bigger. So how will the mixed tensor's diagonal terms sum will be same. Or is it that the metric tensor will be such that when converting those contravariant tensor to mix tensor the other observer's component will be such drastically reduced so that their sum will be the same as the local observer's only component.
 
  • #4
I was overlooking the fact that energy is not Lorentz invariant. If you boost T then the kinetic energy will increase and the gravitational effect should be different.
 
  • #5
Then r u saying that T_mn will not remain invariant under cordinate transformation. If so then how come it became tensor?
 
  • #6
Consider the EM force tensor Fmn. Under Lorentz boost the components of the tensor change, but F2=-(E2-B2) remains the same. Only scalars formed from tensors are invariant. I don't know what the invariants of T are ( or if it has any ).
 
  • #7
Then r u saying that T_mn will not remain invariant under cordinate transformation. If so then how come it became tensor?
Tensors are covariant, not invariant. Their components change under coordinate transformations.
 

FAQ: Help with Stress Tensor: Local vs Other Observers

What is a stress tensor and how is it related to stress?

A stress tensor is a mathematical representation of the stress state of a material or system. It includes both the magnitude and direction of stresses acting on the material. Stress refers to the internal forces that act on a material and can cause it to deform or change shape.

What is the difference between a local and other observers when it comes to stress tensor?

A local observer refers to someone who is directly experiencing the stress in a material, while other observers may be viewing the material from a distance. The stress tensor may be different for these two types of observers, as the magnitude and direction of stresses can vary depending on the perspective.

How does the stress tensor change with different types of materials?

The stress tensor is specific to each material and can change depending on the properties and behavior of the material. For example, a solid material may have a different stress tensor than a fluid material due to their different responses to applied forces.

Can the stress tensor be measured or calculated?

Yes, the stress tensor can be measured or calculated through various techniques such as strain gauges, finite element analysis, and experimental testing. These methods allow scientists to determine the stress state of a material and make predictions about its behavior under different conditions.

How can understanding stress tensor be helpful in real-world applications?

Understanding the stress tensor can be crucial in designing and engineering materials for various applications. It can help predict how a material will respond to external forces and inform decisions about its use in different situations. For example, understanding the stress tensor of a bridge can help engineers ensure its safety and longevity.

Similar threads

Replies
3
Views
1K
Replies
3
Views
2K
Replies
5
Views
1K
Replies
6
Views
2K
Replies
3
Views
1K
Replies
5
Views
3K
Replies
2
Views
1K
Back
Top