- #1
howabout1337
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##\sum_{n=0}^\infty \frac 1{p^{nz}}=1+\frac1{p^z}+\frac1{p^{2z}}+\frac1{p^{3z}}...##
##\frac 1{p^z}\sum_{n=0}^\infty \frac 1{p^{nz}}=\frac1{p^z}+\frac1{p^{2z}}+\frac1{p^{3z}}+\frac1{p^{4z}}...##
something happens and it shows:
##\frac 1{p^z}\sum_{n=0}^\infty \frac 1{p^{nz}}=\sum_{n=0}^\infty\frac1{p^{nz}}-1## <== How can I get here from above
##\frac 1{p^z}\sum_{n=0}^\infty \frac 1{p^{nz}}=\frac1{p^z}+\frac1{p^{2z}}+\frac1{p^{3z}}+\frac1{p^{4z}}...##
something happens and it shows:
##\frac 1{p^z}\sum_{n=0}^\infty \frac 1{p^{nz}}=\sum_{n=0}^\infty\frac1{p^{nz}}-1## <== How can I get here from above
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