How Do You Analyze Motion Using V-T Graphs?

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In summary, the conversation discusses calculating the displacement, velocity, and acceleration of a moving object using a given set of data and sketching a velocity-time graph. The conversation also touches on using the graph to calculate the total displacement of the object. The solution involves using the equation s=ut+(at^2)/2 and taking into account the initial velocity of the object.
  • #1
Dazed
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Homework Statement



distance (cm) 0.0 5.0 15.0 30.0 50.0 75.0 105.0 140.0
time (s) 0.0 0.1 0.2 0.3 0.4 0.50 0.6 0.7

a. calculating the displacement during each time interval. Add to the above table of data.

b. calculating the velocity of the cart during each time interval. Add to the above table of data.

c. sketching a velocity-time graph.

d. calculating the acceleration of the object from the velocity-time graph.

e. Using the velocity-time graph to calculate the total displacement of the cart.


Homework Equations





The Attempt at a Solution



http://www.freewebs.com/dazed42/phys.htm
 
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  • #2
Ok, you've used the right method, and therefore the answer will be correct as long as you've not made any arithmetical errors. The reason for the displacement not equalling the total distance measured will be the same as the previous question, namely that the velocity of the truck at t=0 was no zero.

So, you can use the equation given in the last question to calculate the initial velocity. Recall s=ut+(at^2)/2. Put s=140, t is the total time (0.7s) and a is the acceleration you have calculated.

Really, for the question, you just need to state the the truck was not at rest at t=0, but if you want to check, you can calculate u from the above equation, then add it to each value of v on the graph, giving you a new graph, for which the area underneath will add up to 140cm
 
  • #3
Thanks buddy. From the phrasing of the question I was given the impression that the initial velocity could not be zero. (the cart is at rest before 0 and released at 0, so there must be some instantaneous acceleration)

Much thanks for all the help, I'll be glad to put this behind me now. (Until finals.. whee)

peace,
Dazed
 

FAQ: How Do You Analyze Motion Using V-T Graphs?

What is a V-T graph?

A V-T graph, also known as a velocity-time graph, is a visual representation of an object's velocity over time. It shows the relationship between an object's velocity (y-axis) and time (x-axis), with the slope of the line representing the object's acceleration.

What information can be determined from a V-T graph?

A V-T graph can provide information about an object's velocity, acceleration, and displacement. By analyzing the slope and shape of the graph, you can determine the object's direction of motion, if it is accelerating or decelerating, and its overall motion over time.

How is a V-T graph different from a P-T graph?

A V-T graph shows an object's velocity over time, while a P-T graph shows an object's position over time. In a P-T graph, the slope of the line represents the object's velocity, while in a V-T graph, the slope represents the object's acceleration.

How do you calculate acceleration from a V-T graph?

To calculate acceleration from a V-T graph, you can use the formula a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. The slope of the line on a V-T graph is also equal to the object's acceleration.

What types of motion can be represented on a V-T graph?

A V-T graph can represent various types of motion, including constant velocity, constant acceleration, and changing acceleration (e.g. an object speeding up or slowing down). It can also show motion in different directions, such as forward or backward.

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