How Do You Calculate Sideways Deflection of an Electron in a Magnetic Field?

In summary: What is the radius of the path? Its is simply R = \frac{mv}{qB} which can be written as R = \frac{\sqrt{2mK}}{qB} as you say. Now the question is...is R = 1m? If so, the electron completes a quarter circle and its sideways deflection is merely equal to 1m. Can you see why? (I haven't plugged in your values so I don't know). Even if you get the answer, it would be instructive to figure out how to handle the cases R>1m and R<1m. Draw a top down diagram (as if you are looking down along the negative y axis) of the
  • #1
app
46
0
INTRODUCTION:This is a problem from "Concepts Of Physics" by H.C.Verma.The chapter is "Magnetic Field".

EXACT PROLEM: "An electron is projected horizontally with a kinetic energy of 10 keV.A magnetic field of strength 10^-7 T exists in the vertically upward direction. Calculate the sideways deflection of the electron in traveling through 1m. Make appropriate approximations."

PROBLEM FACED: 1>Travelling through 1m? which 1m? 2> how to calculate the deflection?

WHAT MY BRAIN SUGGESTED: I calculated the radius using √(2Km)/qB. The particlee, since it is negatively charged, will be deflected towards its left, the magnetic force acting towards its right.We have to find the deviation after it has traveled 1m, but how?

CONCLUSION: I am really having problems understanding the above problem. i have just learned "magnetic field", so my concepts are still weak. Please help if you can. Thanks a lot...
 
Physics news on Phys.org
  • #2
app said:
EXACT PROLEM: "An electron is projected horizontally with a kinetic energy of 10 keV.A magnetic field of strength 10^-7 T exists in the vertically upward direction. Calculate the sideways deflection of the electron in traveling through 1m. Make appropriate approximations."

First of all, please draw a diagram if you haven't already done so.

The situation is as follows: the electron has some KE to start with, so it tends to go straight but as soon as it enters the region which has a magnetic field, it gets deflected and deviates from a straight line path.

WHAT MY BRAIN SUGGESTED: I calculated the radius using √(2Km)/qB. The particlee, since it is negatively charged, will be deflected towards its left, the magnetic force acting towards its right.We have to find the deviation after it has traveled 1m, but how?

First you should be able to figure out the direction of this deviation. You are right about the direction, but if you have any doubts, read the following paragraph:

Assume that the initial velocity of the electron is along the +x axis, the magnetic field is along the +y axis. As the electron is negatively charged, it gets deflected in the -z direction. If you are uncomfortable with this, use [itex]\vec{F}=-e(\vec{v}\times\vec{B})[/itex] with [itex]\vec{v} = v\hat{i}[/itex] and [itex]\vec{B} = B\hat{j}[/itex]. Thsi gives [itex]\vec{F} = -evB\hat{k}[/itex].

As the electron travels horizontally, it also gets deflected by the magnetic field...so you have to find out the sideways deflection when the horizontal distance traveled is 1m.

What is the radius of the path? Its is simply [itex]R = \frac{mv}{qB}[/itex] which can be written as [itex]R = \frac{\sqrt{2mK}}{qB}[/itex] as you say. Now the question is...is [itex]R = 1m[/itex]? If so, the electron completes a quarter circle and its sideways deflection is merely equal to 1m. Can you see why? (I haven't plugged in your values so I don't know). Even if you get the answer, it would be instructive to figure out how to handle the cases R>1m and R<1m. Draw a top down diagram (as if you are looking down along the negative y axis) of the electron's circular trajectory and you'll see what I'm saying here.

CONCLUSION: I am really having problems understanding the above problem. i have just learned "magnetic field", so my concepts are still weak. Please help if you can. Thanks a lot...

I recommend reading Resnick/Halliday vol 2 or Resnick/Hallidy/Krane vol 2. And do draw diagrams for even the most trivial seeming questions. And feel free to gets your doubts clarified here. Just keep posting your solutions (in accordance with PF rules).

Hope that helps...
 
Last edited:
  • #3
Does the question state that the path of the deflected electron is a circle? If yes, can use equation of UCM? If not?
 
  • #4
thiotimoline said:
Does the question state that the path of the deflected electron is a circle? If yes, can use equation of UCM? If not?

What makes you think that the path is not circular? And why would the question mention it? Its one of the things you have to figure out.
 
  • #5
thanks for helping...
 
  • #6
app said:
INTRODUCTION:This is a problem from "Concepts Of Physics" by H.C.Verma.The chapter is "Magnetic Field".

EXACT PROLEM: "An electron is projected horizontally with a kinetic energy of 10 keV.A magnetic field of strength 10^-7 T exists in the vertically upward direction. Calculate the sideways deflection of the electron in traveling through 1m. Make appropriate approximations."

PROBLEM FACED: 1>Travelling through 1m? which 1m? 2> how to calculate the deflection?

WHAT MY BRAIN SUGGESTED: I calculated the radius using √(2Km)/qB. The particlee, since it is negatively charged, will be deflected towards its left, the magnetic force acting towards its right.We have to find the deviation after it has traveled 1m, but how?

CONCLUSION: I am really having problems understanding the above problem. i have just learned "magnetic field", so my concepts are still weak. Please help if you can. Thanks a lot...

The 1 meter seems to be the actual distance traveled by the electron (if I read the question properly). So that would be the *arc* of the circle followed by the electron. You also have the radius, so you should be able to figure out the angle (recall, for theta given in radians, you have [itex] s = R \theta [/itex] where "s" is the arc of the circle.

Now it becomes a geometry problem. Draw an arc of circle with the proper angle. You should be able to construct a right angle triangle with the hypothenuse being 1 meter, one side being what you are looking for and the angle being known.

Patrick
 
  • #7
Hey I'm not getting it that way. The answer should be around 1.5 cm but i don't know how. I'm getting the angle theta as 1.186E-13. But after that i can't really follow. Please explain. And is the 1m traveled along the arc or is it 1m along the horizontal direction? If you have time please let me know about both cases. This problem is important for our exam. Please help. Thanks a lot coz i only have words...
 
Last edited:
  • #8
app said:
Hey I'm not getting it that way. The answer should be around 1.5 cm but i don't know how. I'm getting the angle theta as 1.186E-13. But after that i can't really follow. Please explain. And is the 1m traveled along the arc or is it 1m along the horizontal direction? If you have time please let me know about both cases. This problem is important for our exam. Please help. Thanks a lot coz i only have words...

Try what nrqed said. But maybe 1m is the lateral (sweep) distance...

Why don't you post your (complete) working and then have it discussed/checked here.
 

FAQ: How Do You Calculate Sideways Deflection of an Electron in a Magnetic Field?

What is a magnetic field?

A magnetic field is an invisible force field that surrounds any object that has a magnetic field. It is caused by the movement of electric charges, such as in a magnet or an electric current.

How do you calculate the strength of a magnetic field?

The strength of a magnetic field can be calculated using the formula B = μ0I/2πr, where B is the magnetic field strength, μ0 is the permeability of free space, I is the current, and r is the distance from the source of the field.

How do you solve a magnetic field problem?

To solve a magnetic field problem, you will need to use the principles of electromagnetism and apply the relevant equations. First, identify the given information, such as the magnetic field strength or current, and then use the appropriate formula to calculate the unknown variable.

What factors affect the strength of a magnetic field?

The strength of a magnetic field is affected by the magnitude of the current, the distance from the source of the field, and the permeability of the material in the field. The strength also varies with the shape and orientation of the source of the field.

Why is understanding magnetic fields important?

Understanding magnetic fields is important in many areas of science and technology, such as in the design of motors and generators, in medical imaging, and in the study of Earth's magnetic field. It also helps us understand the behavior of charged particles in space and the interactions between electric and magnetic fields.

Back
Top