How Do You Calculate the Initial Velocity Components of a Projectile?

When does it reach the maximum...?Think about it... when does the projectile reach its maximum height?Solve for t when v=0.Then substitute that value into the equation x = x0 + v0 t. That will give you the displacement in the x direction when the projectile is at its maximum height.In summary, the projectile is displaced 40 m horizontally and 53 m vertically above its launch point after 2 seconds. The horizontal velocity component is constant, but not 40 m/s, and the vertical velocity component accelerates at 9.8 m/s^2 downward due to gravity. To find the horizontal and vertical components of the initial velocity, equations are used to
  • #36
kara said:
and b/c I am looking for how far its been displaced horizontally from the launch pt. i am looking for x?
That's right. You are looking for the value of x when y is maximum. Hint: When does it reach the maximum height?
 
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  • #37
well the max height is 53 m, and it reaches that height when v = 0.0 m/s
 
  • #38
i plugged in all my values but get stuck at one point with a negative square root:

53 = -1/2(9.8)t^2
 
  • #39
if i multiply both sides by 2 to get rid of the 1/2 i get

106 = -(9.8) t^2
 
  • #40
kara said:
i plugged in all my values but get stuck at one point with a negative square root:

53 = -1/2(9.8)t^2
You left out part of that equation; it should be:
53 = v0t -1/2(9.8)t^2

Where v0 is the vertical component of initial velocity that you found earlier.
 
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