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Homework Statement
A light bulb is wired in series with a 144Ohm resistor, and they are connected across a 120.0-V source. The power delivered to the light bulb is 23.4W. What is ther resistance of the light bulb? Note that there are two possible answers.
Homework Equations
P = I^2R and I = V/R
The Attempt at a Solution
Solve for I to find Rbulb. I = (V / Rb + Rr)^2 x Rb.
Rearranged 23.4(Rb^2 + 288Rb + 144^2) = 120Rb
This is where I'm stuck, I need to rearrange that so I can get ax^2 + bx + c = 0
My math skills are a little weak since I have been out of school for a few years.
Thanks a lot!