Factorise out the a term on the left side.shanemcguffin said:Solve for a
T - mg = -ma
T = Ma
They get a = mg / (M + m)...how?
I get up to this point... Ma + ma = mg
A system of equations is a set of two or more equations that contain the same variables. These equations are solved simultaneously to find the values of the variables that satisfy all equations in the system.
To solve a system of equations using substitution, you must isolate one variable in one of the equations and substitute it into the other equation. This will create a new equation with only one variable, which can then be solved to find the value of that variable. This value can then be substituted back into the original equations to find the value of the remaining variables.
A consistent system of equations has at least one solution that satisfies all equations in the system. In other words, the equations intersect at one point. An inconsistent system of equations has no solution that satisfies all equations in the system. In this case, the equations are parallel and do not intersect.
Yes, elimination can be used to solve any system of equations. This method involves eliminating one variable by adding or subtracting equations, which ultimately leads to a single equation with one variable that can be solved.
To check if a solution is correct for a system of equations, simply plug in the values of the variables into each equation and see if the equations are satisfied. If all equations are satisfied, then the solution is correct. If one or more equations are not satisfied, then the solution is incorrect.