- #1
Balsam
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Homework Statement
An electric field with a magnitude of 2.5N directed to the left, acts on a negative charge of -5.0C. Determine the electric field in which the charge is located.
Give. FE=2.5N
q=-5.0C
Homework Equations
FE[/B]=qε
The Attempt at a Solution
ε[/B]=2.5N/5.0C=0.5N/C. I don't know how to find the direction. The answer is 0.5N/C,
but I don't know how to get that direction. I guess we have to assume the positive test charge is to the right of q and figure out the direction it would move as a result of FE applied on it by q. That doesn't really make sense though.
Edit: I don't know why the formatting is weird. Also, please help- my exam is tomorrow!
Edit: I don't know why the formatting is weird. Also, please help- my exam is tomorrow!
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