How Does the Radius Affect the Magnetic Field Inside a Solenoid?

In summary, we are trying to find the B field in the axis of an infinitely long solenoid with current I, radius R, and N loops/unit length. Using Amperes law, we can narrow down the equation to B integral dl = Uo I, where the enclosed current Ienc is equal to I*N. The differential length dl is simply L when integrated since the magnetic field runs parallel to the axis of the solenoid. The radius R does not factor into the equation since the B field inside the solenoid is uniform and does not depend on the radius.
  • #1
Chip90
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Homework Statement



There is an infinetly long solenoid with current I, radius R, and N loops/unit length. Find the B field in the axis of the solenoid.

Homework Equations



792d084dfe4651c02d935c1490df17cd.png



The Attempt at a Solution



So that eq. can be narrowed to

B integral dl = Uo I

the only problem is I can't find dl its not 2*pi*R, 2r, 2RN... I am not sure what's wrong here.

I've made a similar diagram where the two edges and the side on the outside have a B field of 0.

solxsect.gif


Any ideas?
 
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  • #2
any ideas? I also got
'
sol2.gif


but now sure how they got that from amperes law? ir is that the answer? thanks.
 

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  • #3
That's correct. The differential length is simply L when integrated, since the magnetic field runs parallel to the axis of the solenoid. The enclosed current Ienc is the current I running through each turn multiplied by the number of turns in the solenoid, or N*I.

Hopefully that helps.
 
  • #4
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?
 
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  • #5
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

You draw the gaussian loop enclosing only half of the inside of the solenoid and the other half s outside. There is no "r" because dl = L when integrated over the length of the solenoid.

Because B does not depend on the radius of the solenoid, the B field inside the solenoid is uniform, much like the E-field between a parallel plate capacitor is uniform.
 
  • #6
ahha that makes sense.. thanks!
 
  • #7
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

The vertical components don't matter since it's a dot product. The length outside of the solenoid is infinitely far away. At a point infinitely far away the magnetic field is 0, therefore it doesn't matter. That leaves the only important part as the horizontal line inside the solenoid. Therefore it's simply L (or X in this case.)
 

FAQ: How Does the Radius Affect the Magnetic Field Inside a Solenoid?

What is a solenoid?

A solenoid is a coil of wire that is typically wound in a helix shape. It is used to create a magnetic field when an electric current passes through it. Solenoids are commonly used in electrical devices such as motors, generators, and relays.

How is the magnetic field of a solenoid calculated?

The magnetic field of a solenoid can be calculated using the equation B = μ₀nI, where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current passing through the solenoid. Alternatively, the magnetic field can also be calculated using the equation B = μ₀NI/L, where N is the total number of turns in the solenoid and L is the length of the solenoid.

What factors affect the strength of the magnetic field in a solenoid?

The strength of the magnetic field in a solenoid is affected by the number of turns in the coil, the current passing through the coil, and the length of the solenoid. Additionally, the type of material used for the core of the solenoid can also impact the strength of the magnetic field.

How does the direction of the magnetic field in a solenoid change with the direction of the current?

The direction of the magnetic field in a solenoid is determined by the right-hand rule. If the current is flowing through the coil in a clockwise direction, the magnetic field will point in the opposite direction, or counterclockwise. If the current is flowing counterclockwise, the magnetic field will point in the opposite direction, or clockwise.

Can the magnetic field of a solenoid be controlled?

Yes, the magnetic field of a solenoid can be controlled by adjusting the current passing through the coil or by changing the number of turns in the coil. This allows for the magnetic field to be turned on and off or adjusted to different strengths, making solenoids useful in a variety of applications.

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