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The superconduction gap equation is:
1=VN(0)arsinh(ωD/lΔl).
My book says that in the weak coupling limit VN(0)<<1 this will reduce to:
lΔl = ωDexp(-1/VN(0))
But how is this obtained. We have:
arsinh(ωD/lΔl) = ln(ωD2+√(ωD2 + lΔl2)), but what has the approximation of this got to do with the prefactor being small? Also I don't see how you get a negative exponent?
1=VN(0)arsinh(ωD/lΔl).
My book says that in the weak coupling limit VN(0)<<1 this will reduce to:
lΔl = ωDexp(-1/VN(0))
But how is this obtained. We have:
arsinh(ωD/lΔl) = ln(ωD2+√(ωD2 + lΔl2)), but what has the approximation of this got to do with the prefactor being small? Also I don't see how you get a negative exponent?