How Is Work Calculated in Elliptical Orbits?

In summary, the conversation discusses the concept of work and force in relation to objects in circular and elliptical orbits. It is explained that parallel force does work and speeds up the object, while perpendicular force does not do work. The difference between parallel and perpendicular force is clarified, with parallel force being in the same direction as the object's movement and perpendicular force being perpendicular to the object's motion.
  • #1
CaptainADHD
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Homework Statement



http://img47.imageshack.us/img47/7206/wtffffftv0.th.jpg http://g.imageshack.us/thpix.php

Homework Equations



Work is the dot product of force vector and displacement vector. Centripetal acceleration is velocity squared divided by radius -- multiply by mass to get force.

The Attempt at a Solution



Parallel does no work, perpendicular speeds it up ----->>> which is wrong (failed this question).

I understand that objects in circular orbit have zero acceleration and thus constant speed. But with elliptical orbits, the body is speeding up or slowing down depending on its position relative to the body exerting gravitational force upon it.

What exactly is parallel to the planet itself? I'm having a hard time understanding how to apply force components when I don't know what the angles are.
 
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  • #2
If I'm following this correctly, it will be the reverse answer of what you gave. Work is done only if there is some motion in the same direction of the force. By parallel, they mean parallel to the movement of the planet, or in the same direction as the V arrow. Perpendicular is perpendicular to the motion, or the force that tries to smash the planet into the sun. It doesn't move that way, so no work by perpendicular, and parallel speeds it up.
 
  • #3
krausr79 said:
If I'm following this correctly, it will be the reverse answer of what you gave. Work is done only if there is some motion in the same direction of the force. By parallel, they mean parallel to the movement of the planet, or in the same direction as the V arrow. Perpendicular is perpendicular to the motion, or the force that tries to smash the planet into the sun. It doesn't move that way, so no work by perpendicular, and parallel speeds it up.

Thanks
 

FAQ: How Is Work Calculated in Elliptical Orbits?

What is work done in an elliptical orbit?

Work done in an elliptical orbit is the amount of energy required to move an object in an elliptical path around a central body, such as a planet or star. This work is a result of the gravitational force between the two bodies.

How does work done in an elliptical orbit differ from work done in a circular orbit?

In a circular orbit, the gravitational force remains constant, resulting in a constant amount of work done. However, in an elliptical orbit, the distance between the two bodies changes, causing the gravitational force and work done to vary throughout the orbit.

What factors affect the amount of work done in an elliptical orbit?

The amount of work done in an elliptical orbit is affected by the mass of the central body, the mass of the orbiting object, and the eccentricity of the orbit. The greater the mass of the central body and the orbiting object, the greater the work done. Similarly, the higher the eccentricity of the orbit, the greater the work done.

How is work done in an elliptical orbit calculated?

The work done in an elliptical orbit can be calculated using the formula W = Fd, where W is the work done, F is the force of gravity, and d is the distance between the two bodies. The force of gravity can be found using Newton's law of universal gravitation, and the distance between the two bodies can be calculated using the semi-major axis of the elliptical orbit.

Can the work done in an elliptical orbit be negative?

Yes, the work done in an elliptical orbit can be negative. This occurs when the orbiting object moves closer to the central body, causing the force of gravity to do negative work. This negative work can be seen in the decrease of the object's kinetic energy as it moves closer to the central body.

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