How to Calculate the Work to Charge a Spherical Shell?

In summary, the problem is to calculate the work required to charge a spherical shell of radius R to a total charge Q. The provided equations include U = k_e\frac{q_1q_2}{r_{12}}, W = -\Delta U, and V = k_e\frac{q}{r} for a sphere. The solution is \frac{k_eQ^2}{2R} and can be found by finding the energy density of an electric field or by considering the stored energy in a set of discrete point charges. The equation \Delta U = -q \int^{A}_{B} \frac{kq}{r^2} dr can be used to find the energy required.
  • #1
thirteen
2
0

Homework Statement


Calculate the work that must be done to charge a spherical shell of radius [tex]R[/tex] to a total charge [tex]Q[/tex].
No diagram was provided.
(Another user posted the same question at https://www.physicsforums.com/showthread.php?t=109489, but there was no solution and the thread is ancient.)

Homework Equations


I'm not sure what equations are needed, so I'm just guessing here.
[tex]U = k_e\frac{q_1q_2}{r_{12}}[/tex]

[tex]W = -\Delta U[/tex]

[tex]V = k_e\frac{q}{r}[/tex] for a sphere

The Attempt at a Solution


I know the answer is [tex]\frac{k_eQ^2}{2R}[/tex] from the back of the book, but I don't know how to get it. I've reread the chapter and all the examples, but I can't find anything talking about energy with just one object. Everything deals with pairs or movement in a field. I thought about making up an identical sphere with charge [tex]-Q[/tex] next to the existing one and finding the change in potential energy. This gets me the right answer, but I doubt that this is a correct process.

Any help would be appreciated.
 
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  • #2
You correctly said [tex]W = - \Delta U[/tex]. Also, keep in mind [tex]\Delta U = -q \int^{A}_{B} E dr[/tex]. Now you can find out what E equals and integrate
 
  • #3
Hi thirteen,

There are several ways to approach this problem. Does your textbook have an expression for the energy density of an electric field? If so, you can integrate that expression over all space to find the energy.

Another approach is to think of the stored energy in a set of discrete point charges, and follow that idea to write out the correct expression for a continuous charge distribution.
 
  • #4
cryptoguy said:
You correctly said [tex]W = - \Delta U[/tex]. Also, keep in mind [tex]\Delta U = -q \int^{A}_{B} E dr[/tex]. Now you can find out what E equals and integrate
Thanks, but I thought that equation was for the movement of a test charge q in a different field. I don't see how it can be used.

alphysicist said:
Hi thirteen,

There are several ways to approach this problem. Does your textbook have an expression for the energy density of an electric field? If so, you can integrate that expression over all space to find the energy.

Another approach is to think of the stored energy in a set of discrete point charges, and follow that idea to write out the correct expression for a continuous charge distribution.
Thanks, I'll look into the latter, since I don't have anything on energy density.
 
  • #5
thirteen said:
Thanks, but I thought that equation was for the movement of a test charge q in a different field. I don't see how it can be used.

It can be used because that is essentially what you are doing: moving a charge from infinity to R against an electric field supplied by the charges you already moved. Another hint:
[tex] E = \frac{kq}{r^2}[/tex] so [tex]\Delta U = -q \int^{A}_{B} \frac{kq}{r^2} dr[/tex]. Integrate that from infinity to R.
 

FAQ: How to Calculate the Work to Charge a Spherical Shell?

What is the formula for calculating the work needed to charge a sphere?

The formula for calculating the work needed to charge a sphere is W = (kQ1Q2)/r, where W is the work in joules (J), k is the Coulomb's constant (9 x 10^9 N*m^2/C^2), Q1 and Q2 are the charges in Coulombs (C) of the two spheres, and r is the distance between the two spheres in meters (m).

How does the distance between the two spheres affect the work needed to charge a sphere?

The work needed to charge a sphere is directly proportional to the distance between the two spheres. This means that as the distance increases, the work needed also increases. This is because the electric force between two charges decreases as the distance between them increases, requiring more work to be done to overcome this force and charge the sphere.

What is the relationship between the charges of the two spheres and the work needed to charge a sphere?

The work needed to charge a sphere is directly proportional to the product of the two charges. This means that as the charges of the two spheres increase, the work needed also increases. This is because the electric force between two charges increases as the charges increase, requiring more work to be done to overcome this force and charge the sphere.

Can the work needed to charge a sphere be negative?

Yes, the work needed to charge a sphere can be negative. This occurs when the charges of the two spheres have the same sign (both positive or both negative). In this case, the electric force between the two charges is repulsive, and work must be done to bring the two spheres closer together. This results in a negative work value.

How does the medium between the two spheres affect the work needed to charge a sphere?

The medium between the two spheres does not affect the work needed to charge a sphere. This is because the work needed to charge a sphere is determined by the properties of the two spheres (their charges and distance) and the Coulomb's constant, which is a fundamental constant of nature and is not affected by the medium between the charges.

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