How to Find the Force Needed to Reduce Acceleration by 50% in Atwood Setup

In summary, in the given Atwood setup with masses m1 = 4.00 kg and m2 = 8.00 kg, an additional force F needs to be applied to m1 to reduce the acceleration of the system by 50%. Using the equations for M1 and M2, with the given acceleration of 3.266/2 m/s^2, the value of F can be solved for by setting T-4g-F=4a and 8g-T=8a and solving for F. The final value of F is 19.596 N.
  • #1
parwana
182
0
4-18.gif


Suppose that in the same Atwood setup another string is attached to the bottom of m1 and a constant force f is applied, retarding the upward motion of m1. If m1 = 4.00 kg and m2 = 8.00 kg, what value of f will reduce the acceleration of the system by 50%?

Now I got the equations for these two as

for M1= T-4g= 4a
for M2= 8g-T= 8a

I got a as 3.266

I got T as 52.264

But I can't get the answer to the asked question. Please HELP me solve this.
 
Physics news on Phys.org
  • #2
Now you have an additional force acting on m1 and a given acceleration. Rewrite your equations accordingly and solve for that force.
 
  • #3
I don't know how to do that, please help
 
  • #4
How did you get those first equations? It's the same analysis, only now there is an additional force acting on m1.
 
  • #5
So is it going to be

T-(4+x)g= (4+x)a

Please help me, I am so fed up of trying to get this right.
 
  • #6
please help, I am so fed up of this problem.
 
  • #7
parwana said:
So is it going to be

T-(4+x)g= (4+x)a

Please help me, I am so fed up of trying to get this right.
No. What you have written assumes mass is being added to m1. No mass is being added. There is an additional force acting, but no additional mass. Also, you have been given the acceleration as half what it was without the additional force, so (a) is now known.
 
  • #8
I don't understand still, can you write it in a equation like I did?
 
  • #9
So will it be

T-4g-F= 4(.5a)

In that case I got F= 19.596
 
  • #10
parwana said:
So will it be

T-4g-F= 4(.5a)

In that case I got F= 19.596
Did you use the old T, or caclulate the new T? The old T will not work.
 
  • #11
Try this. Take your original equations:
parwana said:
for M1= T-4g= 4a
for M2= 8g-T= 8a

I got a as 3.266
Now add the new force F on M1. The equations become:
(for M1) T -4g -F = 4a
(for M2) 8g - T = 8a

You have two unknowns: T and F. Solve for F. (This time around "a" is not an unknown--it's given as 3.266/2 m/s^2.)
 
  • #12
thank u so much
 

FAQ: How to Find the Force Needed to Reduce Acceleration by 50% in Atwood Setup

What is a force majeure clause?

A force majeure clause is a provision in a contract that excuses a party from fulfilling their obligations under the contract in the event of unforeseen circumstances that are beyond their control. These circumstances can include natural disasters, war, strikes, and other events that make it impossible or impractical for the party to fulfill their contractual obligations.

When should a force majeure clause be included in a contract?

A force majeure clause should be included in a contract when there is a possibility of unforeseen events that could make it difficult or impossible for one or both parties to fulfill their obligations. This can include contracts for long-term projects, contracts with international partners, or contracts involving high-risk activities.

What types of events are typically covered by a force majeure clause?

Typically, force majeure clauses cover events that are considered to be outside of human control, such as natural disasters, war, riots, government actions, and labor strikes. However, the specific events covered may vary depending on the language of the clause and the specific contract.

Can a force majeure clause be invoked retroactively?

No, a force majeure clause cannot be invoked retroactively. It can only be invoked in the event of unforeseen circumstances that occur after the contract is signed. If the event was foreseeable at the time the contract was signed, the force majeure clause may not be considered valid.

What should be done if a force majeure event occurs?

If a force majeure event occurs, the party affected should notify the other party as soon as possible and provide evidence of the event and how it has impacted their ability to fulfill their obligations. The parties should then work together to find a solution, such as extending the timeline for fulfilling the contract or amending the terms of the contract. If no solution can be reached, the force majeure clause may allow for the contract to be terminated without penalty.

Similar threads

Accelerating pulleys (3 pulleys and 3 masses)
Replies
5
Views
1K
Why is tension (T) only added to one side of an Atwood Machine?
Replies
3
Views
2K
How Do You Solve a Double Atwood Machine Problem with Unequal Masses?
Replies
1
Views
3K
Mechanics: Two masses on a pulley causing two cylinders to accelerate
Replies
16
Views
1K
What if check: Am I calculating tension wrong?
Replies
3
Views
1K
Atwood Incline Pulley problem with two pulleys
Replies
7
Views
2K
Need Help finding theoretical and actual acceleration (Atwood)
Replies
9
Views
6K
Double pulley Atwood machine (with 3 masses)
3
Replies
97
Views
15K
An Atwoods Machine hanging from the ceiling
Replies
29
Views
4K
What Are the Accelerations and Tensions in a Double Atwood's Machine System?
Replies
8
Views
9K

Hot Threads

Recent Insights

Back
Top