How to Find the Limit of sin(3x²)/(8x) as x Approaches Zero?

In summary: So the final limit is 0.In summary, the limit of sin(3x^2) divided by 8x as x approaches zero is equal to 0. This can be found by factoring out a common term and using the fact that the limit of a constant times a function is equal to the constant times the limit of the function.
  • #1
Dan350
44
0
1.
what would be the limit?? without using the L'Hopital's rule

lim_(x-0) (sin(3 x^2))/(8 x)


the limit of sin(3x^2) divided by 8x as x approaches zero











2. Limits of trignometric functions



3. The Attempt at a Solution
I tried factoring out the 1/8, but that's it, Idk how to go on


Hope you can help me

Thanks


 
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  • #2
Dan350 said:
1.
what would be the limit?? without using the L'Hopital's rule

lim_(x-0) (sin(3 x^2))/(8 x)the limit of sin(3x^2) divided by 8x as x approaches zero


2. Limits of trignometric functions
3. The Attempt at a Solution
I tried factoring out the 1/8, but that's it, Idk how to go onHope you can help me

Thanks

What's lim x->0 of sin(3x^2)/(3x^2)? That should be a good hint.
 
Last edited:
  • #3
Dick said:
What's lim x->0 of sin(3x^2)/(3x^2)? That should be a good hint.



1


but how to put the 3x^2 below?
 
  • #4
Dan350 said:
1but how to put the 3x^2 below?

What (expression) do you have to multiply 8x by to get 3x2? As long as you multiply both the top and bottom by the same, you don't change the fraction.
 
  • #5
Curious3141 said:
What (expression) do you have to multiply 8x by to get 3x2? As long as you multiply both the top and bottom by the same, you don't change the fraction.

3x on both numerator and denominator?
i would get 24x^2, but i can split the fraction right?
 
  • #6
Dan350 said:
3x on both numerator and denominator?
i would get 24x^2, but i can split the fraction right?

So you get ##\frac{3x\sin(3x^2)}{8(3x^2)}##. What happens next?
 
  • #7
Curious3141 said:
So you get ##\frac{3x\sin(3x^2)}{8(3x^2)}##. What happens next?



We factor out.

then the limx-0 of 3x/8 and limx-0 of sin(3x^2)/3x^2
therefore

limx-0 0*1
so

limx-0f(x)= 0
 
  • #8
Dan350 said:
We factor out.

then the limx-0 of 3x/8 and limx-0 of sin(3x^2)/3x^2
therefore

limx-0 0*1
so

limx-0f(x)= 0

Yes, exactly.
 
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FAQ: How to Find the Limit of sin(3x²)/(8x) as x Approaches Zero?

What is the definition of a limit of a trigonometric function?

The limit of a trigonometric function is the value that the function approaches as the input variable approaches a certain value. In other words, it is the value that the function "approaches" but may not necessarily reach at a particular point.

How do you calculate the limit of a trigonometric function?

To calculate the limit of a trigonometric function, you can use algebraic manipulation, trigonometric identities, and the properties of limits. You can also use a graphing calculator or an online limit calculator for more complex functions.

What are the common types of limits of trigonometric functions?

The most common types of limits of trigonometric functions are limits at a specific point, limits at infinity, and limits involving trigonometric identities such as the Squeeze Theorem or the L'Hopital's rule.

How do you determine if a limit of a trigonometric function exists?

A limit of a trigonometric function exists if the left-hand limit and right-hand limit at a particular point are equal. Additionally, if the function is continuous at that point, then the limit exists.

What are the applications of limits of trigonometric functions?

Limits of trigonometric functions are essential in calculus and are used to find the behavior of functions as they approach a particular value or infinity. They are also used in physics, engineering, and other sciences to model and analyze real-world phenomena.

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