- #1
samski
- 60
- 0
Hey, i am using one of these ICs to provide a 3.3V power supply from a li-ion battery. it works well but has an undervoltage lockout of 1.8v, much too low for a lithium ion battery.
here is the datasheet:
http://focus.ti.com/lit/ds/symlink/tps63000.pdf
now it says on the pin descriptions that Vina is the control stage supply... this is also the pin that the undervoltage lockout is measured from. so could i create a potential divider for this pin so that when the li-ion voltage drops to ~2.8V, the chip locks out? what should be the minimum input current for this pin? i can't find a value given in the electrical characteristics -there is a circuit on page 11 which uses a 100R to the vina and other pins. using this and a Vin cut off of 2.9, i calculated 61ohms for the paired resistor. but this gives 18ma current leak, a little high if the battery is left for any time... (its a 1Ah)
sorry if this is in wrong forum
thanks for any help
sam
here is the datasheet:
http://focus.ti.com/lit/ds/symlink/tps63000.pdf
now it says on the pin descriptions that Vina is the control stage supply... this is also the pin that the undervoltage lockout is measured from. so could i create a potential divider for this pin so that when the li-ion voltage drops to ~2.8V, the chip locks out? what should be the minimum input current for this pin? i can't find a value given in the electrical characteristics -there is a circuit on page 11 which uses a 100R to the vina and other pins. using this and a Vin cut off of 2.9, i calculated 61ohms for the paired resistor. but this gives 18ma current leak, a little high if the battery is left for any time... (its a 1Ah)
sorry if this is in wrong forum
thanks for any help
sam