In order to solve for a, you must first isolate the term that contains a. In this case, that term is 3a. To isolate it, you must subtract 7b from both sides of the equation. This will give you the equation 8ab+3a=c-7b. Then, you can factor out the common factor of a, giving you a(8b+3)=c-7b. Finally, divide both sides by (8b+3) to get the value of a.
Yes, you can use substitution to solve for either a or b. To solve for a, you can substitute the value of b into the equation, giving you 8a(3)+7(3)+3a=c. Then, you can solve for a using the same method as mentioned above. To solve for b, you can substitute the value of a into the equation, giving you 8b(c-3)+7b+3(c-3)=c. Then, you can solve for b in the same way.
There is no specific formula for solving equations of this type, but there are some strategies that can make it easier. For example, factoring out common factors and using substitution can help simplify the equation and make it easier to solve for either a or b.
While a graphing calculator can be helpful for graphing the equation and visualizing the relationship between a and b, it is not the most efficient tool for solving this type of equation. It is better to use algebraic methods to solve for a or b.
After solving for a or b, you can plug the value back into the original equation to check if it satisfies the equation. For example, if you solve for a and get the value of a=2, you can plug it into the equation and see if the equation holds true. If the equation is balanced, then you have the correct solution.