- #1
supernova1387
- 31
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I have a question which might be simple.
Suppose we have a 2 degree of freedom system such as a double pendulum which is suspended from the ceiling. Now if the second ball (the lower one) collides with the wall, how can we find the impulse exerted on the ball. I mean do we consider the change in linear momentum JUST for the second ball or do we have to find the center of mass of the system and find the velocity change for the center of mass of the system? Recall that principle of linear momentum states that:
mv1 + Ʃ∫ F*dt= mv2
and the impulse I=Ʃ∫ F*dt
Suppose we have a 2 degree of freedom system such as a double pendulum which is suspended from the ceiling. Now if the second ball (the lower one) collides with the wall, how can we find the impulse exerted on the ball. I mean do we consider the change in linear momentum JUST for the second ball or do we have to find the center of mass of the system and find the velocity change for the center of mass of the system? Recall that principle of linear momentum states that:
mv1 + Ʃ∫ F*dt= mv2
and the impulse I=Ʃ∫ F*dt
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