- #1
Rasine
- 208
- 0
intergrate (ln(x))^2
so i set u=(lnx)^2...which makes du=2lnx(1/x)
then i set dv=dx...which makes v=x
according to the formula for integration by parts i have
x(lnx)^2- integral x(2lnx)(1/x)
simplifying it i get x(ln)^2-2intergral lnx
and here is where i am stuck...what i the integral of lnx?
so i set u=(lnx)^2...which makes du=2lnx(1/x)
then i set dv=dx...which makes v=x
according to the formula for integration by parts i have
x(lnx)^2- integral x(2lnx)(1/x)
simplifying it i get x(ln)^2-2intergral lnx
and here is where i am stuck...what i the integral of lnx?