- #1
goraemon
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Homework Statement
Find an N so that ##∑^{\infty}_{n=1}\frac{log(n)}{n^2}## is between ##∑^{N}_{n=1}\frac{log (n)}{n^2}## and ##∑^{N}_{n=1}\frac{log(n)}{n^2}+0.005.##
Homework Equations
Definite integration
The Attempt at a Solution
I began by taking a definite integral: ##\int^{\infty}_{N}\frac{log(n)}{n^2}dn## and, using integration by parts, arrived at the following answer: ##\frac{log(N)+1}{N}##. (Is this right? If not, I could post the steps I used to try to see where I made an error)
Next we need ##\frac{log(N)+1}{N}## to be within 0.005 as given by the problem, so:
##\frac{log(N)+1}{N}=0.005=\frac{1}{200}##
But I'm having trouble how to solve for N algebraically. Would appreciate any help.