Is Integration by Parts the Key to Solving Complex Equations?

In summary, integration by parts was used to solve the equation ∫e3x*3*x2*ydx=y∫e3x*3*x2dx. The steps involved setting u=3*x2 and dv=e3*xdx, followed by solving for u and v. Further integrations were done using a substitution method until the solution was reached.
  • #1
Ein Krieger
34
0
Hey guys,

Need you push to proceed further with integration by parts:

∫e3x*3*x2*ydx=y∫e3x*3*x2dx

setting u=3*x2-------du=6*x dx
dv= e3*xdx--- v= 1/3* e3*x

∫ e3*x*3*x2*ydx=y*(3*x2* 1/3* e3*x-∫6*x*1/3* e3*xdx)
=y*(3*x2* 1/3* e3*x-6/3*∫x*e3*xdx)
Solving further about x*e3*x
u=x---du=dx
dv=e3*xdx---v=1/3*e3*x
∫ e3*x*3*x2*ydx=y*(3*x2* 1/3* e3*x-6/3*(x*1/3*e3*x-∫1/3e3*x)
 
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  • #2


How can we go further with solution as exp(3*x) repeats all the time?
 
  • #3


You've done all the hard work. ∫e3xdx is easy, using a simple substitution.
 
  • #4


If you have [itex]\int x^n f(x)dx[/itex], where "f" is easy to integrate any number of times (and the "nth" integral of [itex]e^{3x}[/itex] is [itex](1/3^n)e^{3x}[/itex]), just continue taking [itex]u= x^n[/itex], [itex]dv= f(x)dx[/itex]. Everytime du will have x to a lower power until, eventually, it is just [itex]x^0= 1[/itex].
 
  • #5
dx)
=y*(3*x2* 1/3* e3*x-2/9*e3*x-∫2/9*e3*x)
=y*(x2* e3*x-2/9*e3*x2-∫2/9*e3*x2)
=y*(x2* e3*x-2/9*e3*x2-2/9*e3*x3) + C

Integration by parts is a powerful tool in solving complex equations, but it is not always the key to solving them. In some cases, other techniques such as substitution or partial fractions may be more effective. However, integration by parts is a useful method to have in your toolbox, as it allows you to break down an integral into simpler parts and apply different rules to each part. This can be especially helpful when dealing with integrals that involve products of functions, as shown in the example above. With practice and familiarity, integration by parts can be a valuable tool in solving complex equations.
 

FAQ: Is Integration by Parts the Key to Solving Complex Equations?

What is integration by parts?

Integration by parts is a calculus technique used to evaluate integrals that involve products of two functions. It is based on the formula ∫u dv = uv - ∫v du, where u and v are functions and du and dv are their differentials.

How do I know when to use integration by parts?

You can use integration by parts when you have a product of two functions in your integral, and you are unable to find an antiderivative using other techniques such as substitution or the power rule.

Is integration by parts difficult to learn?

Integration by parts can be challenging to understand at first, but with practice, it becomes easier to use. It is essential to understand the concept and the formula thoroughly to be able to apply it correctly.

Can I use integration by parts more than once?

Yes, integration by parts can be used multiple times on the same integral. This is known as repeated integration by parts and can be helpful when the integral involves more than two functions.

What are some tips for successfully using integration by parts?

Some tips for using integration by parts include choosing u and dv strategically, using the LIATE rule to determine u, and being aware of common integrals and their derivatives to simplify the process. It is also crucial to check your answer using the original integral or by differentiating the final result.

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