- #1
hyper
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Hello, this question is about symmetry of polar coordinates.
For a polar-curve to be symmetric around the x-axis we require that if (r,a) lies on the graph then (r,-a) or (-r,Pi-a) lies on the graph.
To be symmetric about the y-axis we require that (-r,-a) or (r,Pi-a) lies on the graph.
Now let's look at the graph r=cos(a/2)
Since cos(-a/2)=cos(a/2) then the curve is symmetric about the x-axis. Of the requirements of symmetri I wrote earlier it doesn't seem to be symmetric about the y-axis. But when I draw it, symmetry about the y-axis occours. How can this be shown mathematically?
hyper
For a polar-curve to be symmetric around the x-axis we require that if (r,a) lies on the graph then (r,-a) or (-r,Pi-a) lies on the graph.
To be symmetric about the y-axis we require that (-r,-a) or (r,Pi-a) lies on the graph.
Now let's look at the graph r=cos(a/2)
Since cos(-a/2)=cos(a/2) then the curve is symmetric about the x-axis. Of the requirements of symmetri I wrote earlier it doesn't seem to be symmetric about the y-axis. But when I draw it, symmetry about the y-axis occours. How can this be shown mathematically?
hyper