Is the Time to Discharge a Capacitor Always the Same Number of Time Constants?

In summary, the conversation discusses the discharge of a capacitor and the time required to reach a fully discharged state. It is stated that for practical purposes, a capacitor can be considered fully discharged after a finite length of time, although the equation implies an infinite amount of time is required. Part C poses the question of whether the time required to reach this state is always the same number of time constants, independent of the values of capacitance and resistance. The answer provided is yes, and it is explained that for any RC circuit with varying choices of R and C, the ratio of the defined discharge time to the circuit time constant is simply related to the ratio of e/Q_0. This is further supported by a rearranged equation that shows the
  • #1
hokie1020
2
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Strictly speaking, the equation q=Q_0e^{-t/RC} implies that an infinite amount of time is required to discharge a capacitor completely. Yet for practical purposes, a capacitor may be considered to be fully discharged after a finite length of time. To be specific, consider a capacitor with capacitance C connected to a resistor R to be fully discharged if its charge q differs from zero by no more than the charge of one electron.

I could do everything except explaining why Part C's answer is correct
Part A
Calculate the time required to reach this state if C = 0.910 microF, R = 690 kilo ohms, and Q_0 = 6.80 microC.
t=19.7s
Part B
How many time constants is this?
31.4 time constants
Part C
For a given Q_0, is the time required to reach this state always the same number of time constants, independent of the values of C and R?
yes
Part D
Why or why not? (in response to Part C)




Part D is what i can't explain. Can anyone help?
 
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  • #2
If you rearrange the charge equation (which is the solution to the differential equation produced by Kirchkoff's circuit rules) for the situation where the capacitor discharges to q(T) = e (one fundamental charge), we have

e/Q_0 = e^(-T/RC) .

I think what they're saying is this: for any RC circuit with varying choices of R and C, and starting with a fully-charged capacitor, the ratio of this defined discharge time to the circuit time constant is simply related to the ratio of e/Q_0 .
[EDIT: Re-reading the question once again, I agree with their answer; the equation above shows why. Try it with numbers to satisfy yourself -- I had to...]
 
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  • #3


The reason why the time required to reach a fully discharged state is always the same number of time constants, regardless of the values of C and R, is because the equation q=Q_0e^{-t/RC} is an exponential function. This means that as time increases, the charge on the capacitor decreases exponentially. The time constant, denoted as τ, is a measure of how quickly the exponential function decays. It is calculated as τ = RC, where R is the resistance and C is the capacitance.

Since the time constant τ is a product of C and R, any changes in these values will result in a proportional change in τ. However, the ratio of C to R will remain the same, and therefore the time constant will remain the same. This means that no matter what values of C and R are used, the time required to reach a fully discharged state will always be the same number of time constants.

In simpler terms, the time constant is a characteristic property of the RC circuit, and it does not change based on the specific values of C and R. Therefore, the time required to reach a fully discharged state will always be consistent, regardless of the values of C and R.
 

FAQ: Is the Time to Discharge a Capacitor Always the Same Number of Time Constants?

What is an RC Circuit and how does it work?

An RC circuit is a circuit that contains a resistor (R) and a capacitor (C) connected in series. The resistor limits the flow of current in the circuit, while the capacitor stores electrical charge. When a voltage is applied to the circuit, the capacitor charges up until it reaches its maximum capacity, at which point the current stops flowing. As the capacitor discharges, the current starts flowing again. This process repeats, creating an oscillating current in the circuit.

How do you calculate the time constant in an RC circuit?

The time constant (τ) in an RC circuit is calculated by multiplying the resistance (R) and the capacitance (C) of the circuit. This can be represented by the formula τ = RC.

What is the relationship between charge and voltage in an RC circuit?

The voltage across a capacitor in an RC circuit is directly proportional to the charge on the capacitor. This means that as the charge on the capacitor increases, the voltage across it also increases, and vice versa.

What happens to the charge on a capacitor when the circuit is disconnected?

When the circuit is disconnected, the charge on the capacitor remains constant. This is because the capacitor acts as an insulator, preventing the flow of current. Therefore, the charge cannot escape and remains stored on the capacitor until the circuit is reconnected.

How does changing the resistance or capacitance affect the charging and discharging of an RC circuit?

Changing the resistance in an RC circuit affects the rate at which the capacitor charges and discharges. A higher resistance will result in a slower charging and discharging process, while a lower resistance will result in a faster process. Similarly, changing the capacitance affects the amount of charge that can be stored on the capacitor, and therefore also affects the rate of charging and discharging.

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