Limit Sum Riemann: Solve Homework Problem

In summary: The Attempt at a SolutionI don't know how to start this problem...Help me please, thank you."With Riemann" means that you treat this as a Riemann sum- which is used to define the definite integral.If we divide the x-axis, from x= a to x= b, into n intervals then each interval has length [itex]\Delta x= (b-a)/n. And, if we take the value of the integrand, f, in each interval at the left end of that interval, we have f((b-a)k/n) as the height of the rectangle we are forming on that interval so its area is
  • #1
Molina
3
0

Homework Statement



Calculate the limit with Riemann.

Homework Equations



[tex]\displaystyle\lim_{n \to{+}\infty}{\displaystyle\frac{pi}{4}\cdot{} \displaystyle\sum_{k=0}^n{tan^2(\displaystyle\frac{k\cdot{} pi}{4n})\cdot{}\displaystyle\frac{1}{n}}}[/tex]

The Attempt at a Solution



I don't know how to start this problem...

Help me please, thank you.
 
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  • #2
"With Riemann" means that you treat this as a Riemann sum- which is used to define the definite integral.

If we divide the x-axis, from x= a to x= b, into n intervals then each interval has length [itex]\Delta x= (b- a)/n[itex]. And, if we take the value of the integrand, f, in each interval at the left end of that interval, we have f((b-a)k/n) as the height of the rectangle we are forming on that interval so its area is f((b-a)k/n)(b-a)/n and the whole arera is
[tex]\displaystyle (b- a)\sum_{k=0}^n f((b-a)k/n)\cdot\frac{1}{n}[tex]
The limit turns that into an integral.

So you need to indentify f(x), a, and b in this particular sum, and integrate.
 
  • #3
Explain me in this case please, is the first time I have to do one problem like this. Thank you
 
  • #4
Halls' already explained it, you just have to put in a bit of effort into trying to understand what he said. Some of his code didn't appear properly so I'll put it up again for you.

HallsofIvy said:
"With Riemann" means that you treat this as a Riemann sum- which is used to define the definite integral.

If we divide the x-axis, from [itex]x= a[/itex] to [itex]x= b[/itex], into [itex]n[/itex] intervals then each interval has length [itex]\Delta x= (b-a)/n[/itex]. And, if we take the value of the integrand, [tex]f(x)[/tex], in each interval at the left end of that interval, we have [tex] f\left(\frac{(b-a)k}{n}\right)[/tex] as the height of the rectangle we are forming on that interval so its area is [tex]f(\frac{(b-a)k}{n})\left(\frac{b-a}{n}\right)[/tex] and the whole area is
[tex]\displaystyle (b- a)\sum_{k=0}^n f\left( \frac{(b-a)k}{n}\right)\cdot\frac{1}{n}[/tex]
If we take the limit as the number of rectangles [itex] n \to \infty [/itex] this becomes [tex] \int^b_a f(x) dx [/tex].
So you need to indentify f(x), a, and b in this particular sum, and integrate.

So carry you this idea for an easy (and common) case, [tex] \int^1_0 f(x) dx [/tex]. You want to find an expression for Riemann sums for that integral. If you do the same idea as what Halls described already, you should get [tex] \int^1_0 f(x) dx = \lim_{n\to\infty} \frac{1}{n} \sum_{k=1}^{n} f\left(\frac{k}{n}\right) [/tex].
 
  • #5
I'm sorry but I don't understand, how i know a and b? I'm sorry I'm lost.

I have the idea.. b is [tex]pi / 4[/tex] and [tex]a = 0[/tex] ?

And f(x) = [tex]tan^2(k*pi/4n)[/tex] ? ?
 

FAQ: Limit Sum Riemann: Solve Homework Problem

What is the Riemann sum?

The Riemann sum is a method for approximating the area under a curve by dividing it into smaller rectangles and calculating the sum of their areas. It is often used in calculus to find the definite integral of a function.

What is the limit sum Riemann?

The limit sum Riemann is a more precise version of the Riemann sum, where the width of the rectangles approaches zero. This allows for a more accurate approximation of the area under the curve and is often used in advanced calculus and analysis.

How do I solve a homework problem involving limit sum Riemann?

To solve a homework problem involving limit sum Riemann, you will need to follow a few key steps. First, determine the function and the interval over which you need to find the area. Then, choose the number of rectangles to use in your approximation. Next, calculate the width of each rectangle and the height of each rectangle using the function. Finally, add up the areas of each rectangle to get your final answer.

What are the benefits of using limit sum Riemann?

Limit sum Riemann allows for a more accurate approximation of the area under a curve compared to other methods. It is also a fundamental concept in calculus and can be used to solve a wide range of problems in mathematics and physics.

Are there any limitations to using limit sum Riemann?

While limit sum Riemann is a powerful tool in calculus, it does have some limitations. It may not always be possible to find an exact solution using this method, and it can be time-consuming for complex functions. Additionally, using a larger number of rectangles can lead to a more accurate approximation, but it also requires more calculations.

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