Limits with Trigonometric Functions and Polynomials

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In summary, the limit of cos(x) as x approaches 0 is 1. However, the limit can be negative depending on the value of x. It is equal to the value of cos(0), which is 1. A one-sided limit only considers one side while a two-sided limit considers both sides. The limit of cos(x) cannot exceed 1 or -1, but it can approach these values as x approaches certain values such as π/2 or -π/2.
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Homework Statement



solve the limit:

[tex]\lim_{x\rightarrow0}\frac{2cos^{2}(x)-cos(x)-3}{x^{2}}[/tex]


The Attempt at a Solution



Ok so i factored out the numerator, but i don't know where to go from there any help please.

[tex]\lim_{x\rightarrow0}\frac{2cos^{2}(x)-cos(x)-3}{x^{2}}=\lim_{x\rightarrow0}=\frac{(2cos(x)-3)(cos(x)+1)}{x^{2}}[/tex]
 
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Alright never mind i got limit as x approaches 0 to equal -∞.
 

FAQ: Limits with Trigonometric Functions and Polynomials

What is the limit of cos(x) as x approaches 0?

The limit of cos(x) as x approaches 0 is 1.

Can the limit of cos(x) be negative?

Yes, the limit of cos(x) can be negative depending on the value of x. For example, if x is approaching π, the limit would be -1.

Is the limit of cos(x) equal to the value of cos(0)?

Yes, the limit of cos(x) is equal to the value of cos(0), which is 1.

What is the difference between a one-sided limit and a two-sided limit?

A one-sided limit only considers the values of a function as x approaches a particular value from one side (either the left or right), while a two-sided limit considers both sides. For example, the one-sided limit of cos(x) as x approaches 0 from the left would be -1, while the two-sided limit would be 1.

Can the limit of cos(x) exceed 1 or -1?

No, the limit of cos(x) cannot exceed 1 or -1 as those are the maximum and minimum values of the cosine function. However, the limit can approach these values as x approaches certain values such as π/2 or -π/2.

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