Linear FE for static, spherical body

In summary, you need to set up a spherical polar coordinate system and solve the Laplace equation for the potential.
  • #1
WannabeNewton
Science Advisor
5,844
552
How exactly would I go about finding the components of [tex]h_{ab}[/tex] of the linear vacuum field equations for the external gravitational field of a static, spherical body situated at x = y = z = 0 for all t? I assumed since x = y = z = 0 for all t all [tex]h_{ab}[/tex],x and ,y and ,z terms vanish from the Riemann tensor. Do I go about solving [tex]R_{ab}[/tex] = 0 for [tex]h_{ab}[/tex] because I can't really see where the spherical part comes in.
 
Physics news on Phys.org
  • #2
WannabeNewton said:
How exactly would I go about finding the components of [tex]h_{ab}[/tex] of the linear vacuum field equations for the external gravitational field of a static, spherical body situated at x = y = z = 0 for all t? I assumed since x = y = z = 0 for all t all [tex]h_{ab}[/tex],x and ,y and ,z terms vanish from the Riemann tensor. Do I go about solving [tex]R_{ab}[/tex] = 0 for [tex]h_{ab}[/tex] because I can't really see where the spherical part comes in.

Use spherical polar coordinates and let hab=hab(r) be a function of r only. Then you'll have spherical symmetry.
 
  • #3
I just don't get what to do with the linear field equations in this case: [tex]\nabla[/tex][tex]_{\alpha }[/tex][tex]\nabla[/tex][tex]_{\alpha }[/tex][tex]h_{\mu \nu }[/tex]= 0
([tex]\alpha[/tex]s should be lower indexes sorry)
with [tex]g_{\mu \nu }[/tex] = diag(-1, 1, r[tex]^{2}[/tex], r[tex]^{2}[/tex]sin[tex]^{2}\theta[/tex])

Do I set up a generalized metric like one would for the full field equations?
 
  • #4
The linear theory is a sort of local theory and assumes we can use approximately Cartesian coords, so my first post is wrong.

It's a tricky business deriving the linearized field equations. I recommend you look it up in a textbook,
or have a look at this

http://www.lehigh.edu/~kdw5/project/howto1.pdf
 
Last edited by a moderator:
  • #5
The linearized field obeys the linear wave equation, or in this time-independent case Laplace's equation. With spherical symmetry it's just like the electrostatic potential for the Coulomb field of a charge, h ~ m/r. Put together solutions of this form that satisfy your gauge condition.
 
  • #6
I'm actually fine on the derivation. The subsequent solution for the plane gravitational wave was pretty straight forward too. I'm just confused with what to do with the field equations and the Lorentz gauge in the case of curvilinear coordinates like in this situation.
 

FAQ: Linear FE for static, spherical body

What is linear FE for static, spherical body?

Linear FE (Finite Element) for static, spherical body is a method used in computational mechanics to analyze the behavior of a spherical body under static conditions. It involves dividing the body into smaller, simpler geometric shapes called finite elements, and using mathematical equations to model the behavior of each element and its interactions with neighboring elements. This method allows for the prediction of stress and deformation in the body, which can be used for various engineering applications.

How is linear FE for static, spherical body different from other FE methods?

Linear FE for static, spherical body is specifically designed for analyzing spherical bodies, whereas other FE methods may be used for different shapes and types of structures. Additionally, linear FE for static, spherical body assumes that the material properties of the body remain constant and that the body is under static loading conditions, whereas other FE methods may account for variable material properties and dynamic loading scenarios.

What are the advantages of using linear FE for static, spherical body?

One advantage of using linear FE for static, spherical body is its ability to handle complex geometries. By dividing the body into smaller finite elements, the analysis can be applied to irregular shapes and structures. Additionally, linear FE is relatively easy to implement and can provide accurate results for a wide range of problems.

What are the limitations of linear FE for static, spherical body?

One limitation of linear FE for static, spherical body is its assumption of linear behavior in the material. This means that it may not accurately model nonlinear materials or behaviors, such as plastic deformation or large displacements. Additionally, the accuracy of the results can be affected by the mesh size and element shape used in the analysis.

What are some applications of linear FE for static, spherical body?

Linear FE for static, spherical body has various applications in engineering, including stress and deformation analysis of pressure vessels, piping systems, and spherical tanks. It can also be used for analyzing the stability and strength of underground structures, such as tunnels and caverns, and for predicting the behavior of spherical components in mechanical systems, such as bearings and gears.

Similar threads

Back
Top