- #1
UrbanXrisis
- 1,196
- 1
when:
g'(2)=1
g'(3)= -2
msec=mtan
g'(2.5)=(y2-y1)/(x2-x1)
=(-2-1)/(3-2)
=-3/1
=-3
I got this question wrong on a test, were was my mistake?
g'(2)=1
g'(3)= -2
msec=mtan
g'(2.5)=(y2-y1)/(x2-x1)
=(-2-1)/(3-2)
=-3/1
=-3
I got this question wrong on a test, were was my mistake?