- #1
Ronankeating
- 63
- 0
Hi All,
Basically I 've 2 question in mind.
To elaborate the 2nd question:
The 2nd question above is usually named Floor by Floor Assembly(FFA) in structural eng. Where floors are assumed as rigid diphragm and whole floor weight is lumped at the mass or rigidity center of floor. Each floor will have only [itex]\delta_x[/itex], [itex]\delta_y[/itex] and [itex]\theta_z[/itex] two translational and one rotational degree of freedom(as per the code request) and will be treated as master, other joints as slave. FEM books suggest to transfer slave joint mass and force stiffness to master joint, but in my case slave joints are massless and whole floor weight will be at the mass center. So basically what those mx, my and mz should look like in reduced mass matrix.
Master Mass Matrix
\begin{bmatrix}m_x &0&0\\0&m_y&0\\0&0&m_z \end{bmatrix}
Can I assume ??
mx = (Total weight of Floor) /3
mY = (Total weight of Floor )/3
mz = (Total weight of Floor) /3
Best Regards,
Basically I 've 2 question in mind.
- If I use always consistent masses in my calculations, does that mean that I'm always doing more exact analysis and obtaining the more exact results than lumped mass techniques, with sacrifacing the computer storage?
- If I choose lumped masses, and if I do some reductions due to unwanted degrees of freedom. Then what like should that mass look after the reduction with lumped masses?
To elaborate the 2nd question:
The 2nd question above is usually named Floor by Floor Assembly(FFA) in structural eng. Where floors are assumed as rigid diphragm and whole floor weight is lumped at the mass or rigidity center of floor. Each floor will have only [itex]\delta_x[/itex], [itex]\delta_y[/itex] and [itex]\theta_z[/itex] two translational and one rotational degree of freedom(as per the code request) and will be treated as master, other joints as slave. FEM books suggest to transfer slave joint mass and force stiffness to master joint, but in my case slave joints are massless and whole floor weight will be at the mass center. So basically what those mx, my and mz should look like in reduced mass matrix.
Master Mass Matrix
\begin{bmatrix}m_x &0&0\\0&m_y&0\\0&0&m_z \end{bmatrix}
Can I assume ??
mx = (Total weight of Floor) /3
mY = (Total weight of Floor )/3
mz = (Total weight of Floor) /3
Best Regards,