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AnthreX
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can mass changed to energy
and can energy changed to mass ?
if no why ?
and can energy changed to mass ?
if no why ?
From this we could also conclude that photons have mass
chroot said:Because momentum in relativistic mechanics is defined more generally than in classical mechanics. In relativistic mechanics, the energy of a particle is related to its momentum via
[tex]E = \sqrt{p^2 c^2 + m_0^2 c^4}[/tex]
where E is the energy, p is the momentum, [itex]m_0[/itex] is the rest-mass, and c is the speed of light. Energy can come in several forms: kinetic energy, rest-mass energy, and so on. Thus, a photon does not need mass to have momentum. This definition winds up being precisely the same as the classical definition when you consider particles that aren't moving very fast, so the two are not incompatible; it just happens that the relativistic version applies everywhere (as far as we currently know anyway), while the classical version has restrictions on where it can be applied.
- Warren
No.Michael F. Dmitriyev said:Does it not means that radiation is the TWO DIMENSIONAL PRODUCT of light (c^2) and an object having mass is a FOUR DIMENSIONAL PRODUCT of light (c^4) ?
Why?chroot said:No.
- Warren
Mostly by default. The assertion that "radiation is the two dimensional product of light" doesn't even make sense. I'm going to warn you, as well, to resist the temptation to post your personal theories in parts of the site where they are unwelcome.Michael F. Dmitriyev said:Why?
-Michael
Cheman has \ correctly deduced that light has mass. re - he was correct when he saidchroot said:You did not ask a question, you made an assertion which concluded that light has mass.
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Because momentum in relativistic mechanics is defined more generally than in classical mechanics. In relativistic mechanics, the energy of a particle is related to its momentum via
[tex]E = \sqrt{p^2 c^2 + m_0^2 c^4}[/tex]
where E is the energy, p is the momentum, [itex]m_0[/itex] is the rest-mass, and c is the speed of light. Energy can come in several forms: kinetic energy, rest-mass energy, and so on. Thus, a photon does not need mass to have momentum. This definition winds up being precisely the same as the classical definition when you consider particles that aren't moving very fast, so the two are not incompatible; it just happens that the relativistic version applies everywhere (as far as we currently know anyway), while the classical version has restrictions on where it can be applied.
- Warren
In your comment above you posted the correct relationship between inertial energy, rest mass and momentum. You then used the term "mass" unqualfied to mean "rest mass" as you have in previous posts and threads in this forum. Cheman does not seem to be aware of the semantics of this point and that is where the disagreement is. Once more we're back to the debate of what the term "mass" means.Hence, if a photon lacks mass then how can it have momentum if momentum = mass * velocity?
But there is, fortunately, a grave fault in the reasoning of the inside observer, which saves our previous conclusion. He said: “A beam of light is weightless and, therefore, it will not be affected by the gravitational field.” This cannot be right! A beam of light carries energy and energy has mass.