- #1
Katy96
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Homework Statement
Homework Equations
The Attempt at a Solution
any help would be appreciated! I keep trying and just keep getting stuck really early on.
I suppose you mean Equation 1?Katy96 said:I don't understand where the first differential comes from
And how would you apply ΣF = ma to the problem with the mass and spring?Katy96 said:yes force= mass*acceleration
Well, what forces are acting on the mass? If you assume the mass is at rest at point O, and you move it x-distance to the right, what happens to the spring? What does the displacement of the spring do to the mass?Katy96 said:that's where I get stuck
the spring is stretched so will want to go back to its original placeSteamKing said:Well, what forces are acting on the mass? If you assume the mass is at rest at point O, and you move it x-distance to the right, what happens to the spring? What does the displacement of the spring do to the mass?
Yes, but what does the tendency of the spring to unstretch itself do to the mass? What does it take to stretch the spring in the first place?Katy96 said:the spring is stretched so will want to go back to its original place
it has to be stretched by something and to go back to its original it passes and oscillatesSteamKing said:Yes, but what does the tendency of the spring to unstretch itself do to the mass? What does it take to stretch the spring in the first place?
What is this something? Do you know about Hooke's Law?Katy96 said:it has to be stretched by something and to go back to its original it passes and oscillates
yeah F=-kXSteamKing said:
In your problem, you move the mass a distance x. What does that create in the spring? Make the mass a free body and label all the forces acting on it.Katy96 said:yeah F=-kX
First thing's first: you need to draw a good free body diagram. Label all the forces acting on the mass and their directions. The sum of these forces will be equal to the mass * the acceleration of the body (remember ##a(t) = \ddot{x}(t)##) , and the required DE will fall out pretty quickly from this.Katy96 said:that's where I get stuck
The equation for the period of a mass on a spring is T = 2π√(m/k), where T is the period in seconds, m is the mass of the object in kilograms, and k is the spring constant in Newtons per meter.
The period of a mass on a spring is directly proportional to the square root of the mass. This means that as the mass increases, the period also increases. However, the period is also affected by the spring constant, so the relationship is not linear.
The period of a mass on a spring is inversely proportional to the square root of the spring constant. This means that as the spring constant increases, the period decreases. This relationship is also affected by the mass of the object attached to the spring.
The amplitude of a mass on a spring does not affect the period. The period is only affected by the mass, spring constant, and gravitational force acting on the object. However, the amplitude does affect the maximum displacement and velocity of the object.
The period of a mass on a spring is not affected by gravity. This is because the period is determined by the mass and spring constant, which do not change with the force of gravity. However, gravity does affect the equilibrium position of the mass on the spring, as well as the amplitude of the oscillations.