- #1
self_study
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Show that the maximum area of a triangle corresponds to the triangle being equilateral.
I start by making y the height of the triangle and x a leg.
We have two formulas (for area)
A = xy/2
A = sqrt(s(s-a)(s-b)(s-x))
I'm thinking that in order to find the maximum, we must make dA/dx = 0 and show that x=a=b . Any suggestions on how to do this?
Forgive me if this is really easy, I've been out of school for some time and have forgotten alot--trying to learn again.
I start by making y the height of the triangle and x a leg.
We have two formulas (for area)
A = xy/2
A = sqrt(s(s-a)(s-b)(s-x))
I'm thinking that in order to find the maximum, we must make dA/dx = 0 and show that x=a=b . Any suggestions on how to do this?
Forgive me if this is really easy, I've been out of school for some time and have forgotten alot--trying to learn again.