- #1
Amineen
- 3
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hi..how can i simplify this..i tried on mathematica but i am getting nothing but the same expression\noindent\(\pmb{-e^{-x} \left(1-e^{-x}\right)^{-1+\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{$\alpha $1}+\text{$\alpha $2}}
\left(-1+\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $3}}\right) (\text{$\alpha $1}+\text{$\alpha $2}) \beta +}\\
\pmb{\frac{\left(1-e^{-x}\right)^{\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{$\alpha $1}+\text{$\alpha $3}} \left(\text{$\alpha
$1}+\text{$\alpha $3}-\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $2}} \text{$\alpha $3}\right) \beta }{-1+e^x}}\)
(mentor note: tried to fix this but it didn't look right)
\left(-1+\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $3}}\right) (\text{$\alpha $1}+\text{$\alpha $2}) \beta +}\\
\pmb{\frac{\left(1-e^{-x}\right)^{\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{$\alpha $1}+\text{$\alpha $3}} \left(\text{$\alpha
$1}+\text{$\alpha $3}-\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $2}} \text{$\alpha $3}\right) \beta }{-1+e^x}}\)
(mentor note: tried to fix this but it didn't look right)
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