On the possibility of making an engine with efficiency 1

In summary: This fact does not imply that the maximum work is not equal to ΔU. Indeed for a constant volume process δWrev=δQrev = dU. Yet for a general process we have shown that δWrev = -dG.
  • #1
Joyal Babu
25
3
https://www.researchgate.net/post/Gibbs_free_energy_U-TS_PVIn_a_high_pressure_environment_when_PV_equals_TS_can_we_actually_use_the_entire_internal_energy_of_a_system_to_do_work?_iepl%5BviewId%5D=EMvZ8y3kBTyHiPzK6A8YVYvn&_iepl%5BsingleItemViewId%5D=erF86LeZ0BmbObFXKscz92Ib&_iepl%5BactivityId%5D=725672637112320&_iepl%5BactivityType%5D=person_post_question&_iepl%5BactivityTimestamp%5D=1467455039&_iepl%5BhomeFeedVariantCode%5D=d_EU&_iepl%5Bcontexts%5D%5B0%5D=homeFeed&_iepl%5BinteractionType%5D=questionView

If so can an engine be devised to use its entire internal energy to do work
 
Last edited by a moderator:
Science news on Phys.org
  • #2
Joyal Babu said:
https://www.researchgate.net/post/Gibbs_free_energy_U-TS_PVIn_a_high_pressure_environment_when_PV_equals_TS_can_we_actually_use_the_entire_internal_energy_of_a_system_to_do_work?_iepl%5BviewId%5D=EMvZ8y3kBTyHiPzK6A8YVYvn&_iepl%5BsingleItemViewId%5D=erF86LeZ0BmbObFXKscz92Ib&_iepl%5BactivityId%5D=725672637112320&_iepl%5BactivityType%5D=person_post_question&_iepl%5BactivityTimestamp%5D=1467455039&_iepl%5BhomeFeedVariantCode%5D=d_EU&_iepl%5Bcontexts%5D%5B0%5D=homeFeed&_iepl%5BinteractionType%5D=questionView

If so can an engine be devised to use its entire internal energy to do work
no such thing as a free energy engine
please reread the PF rules that you should have read when you signed up

discussion of these topics are not allowed
 
Last edited by a moderator:
  • #3
davenn said:
no such thing as a free energy engine
please reread the PF rules that you should have read when you signed up

discussion of these topics are not allowed

Indeed. Thread locked.
 
  • #4
@Useful nucleus contacted and convinced the mentors that an explanation of some basic thermodynamics would be useful to the OP and to others. As threads this close to being about PMM's tend to attract crackpots, the thread will remain locked but has been un-deleted. The following explanation was composed by Useful Nucleus and anyone with questions about it should start a new thread.

Gibbs free energy G is not the available work. G is a state function describing a single state whereas work is a process from one state to another. What we can show is that the work delivered in a reversible process by a system in contact with a thermal reservoir and a pressure reservoir is equal to the decrease in Gibbs free energy. That is δW= - dG. Notice that the fact that process is reversible indicates that this is the maximum possible work delivered between the initial state and final state (Maximum work theorem).

To be more concrete I adopt Problem 4.5-20 form the excellent Thermodynamics text by Herbert Callen.
Suppose a system is in some initial state and is planned to deliver maximum work while going from this initial state to a final state. The final state is decided by that fact that it has to be in equilibrium with the ambient atmosphere which acts as a temperature and pressure reservoir (Tatm , Patm are fixed). To deliver maximum work the process has to be reversible. You can show that the maximum work is NOT -ΔU because there will be heat loss to the reservoir and even worse there will be work loss to the reservoir as well! So the maximum work is:

W= (U0 + Patm V0 - Tatm S0) - (Uf + Patm Vf - Tatm Sf)

The latter equation can be derived without any reference to Gibbs free energy and in fact historically it was the precursor to coin the term free energy.
In summary it is not correct to think of G itself as the available work, rather one has to consider the decrease in G.
 

FAQ: On the possibility of making an engine with efficiency 1

Can an engine really have 100% efficiency?

Currently, no engine can have 100% efficiency. This is because of the second law of thermodynamics, which states that energy cannot be fully converted into work without any waste. However, scientists are constantly researching and developing new technologies to improve engine efficiency.

Why is it difficult to achieve 100% efficiency in engines?

Engine efficiency is limited by factors such as friction, heat loss, and incomplete combustion. These inefficiencies result in lost energy, making it difficult to achieve 100% efficiency. Additionally, the laws of thermodynamics place limits on how much energy can be converted into work.

Can renewable energy sources achieve 100% efficiency?

Renewable energy sources such as solar and wind energy can have high efficiency rates, but they cannot achieve 100% efficiency. This is because they also face limitations such as weather conditions and the ability to convert energy into usable forms.

How can we improve engine efficiency?

Improving engine efficiency requires a combination of innovative technologies and better design. This can include reducing friction, improving heat management, and optimizing combustion processes. Additionally, using alternative fuels and energy sources can also contribute to increased efficiency.

What are the benefits of having an engine with 100% efficiency?

An engine with 100% efficiency would have little to no waste, resulting in lower energy consumption and reduced emissions. This would lead to cost savings, improved environmental sustainability, and a more efficient use of resources. It could also open up new possibilities for transportation and energy production.

Back
Top