Operator representation of p in x basis.

In summary, the Schrodinger equation for a hydrogen atom involves writing out the operator for the electron's momentum, p^2/2m, in a positional basis with four discrete points. The operator notation for this would include the basis states and the Hamiltonian operator with terms for the electron's momentum and the Coulombic potential between the electron and the nucleus.
  • #1
qubits
7
0
For the Schrodinger equation for a hydrogen atom, we need to write out:

p^2/2m for the electron.

If we define our basis states to be a linear discrete array of points, let's say 4 points. 0,d,2d, and 3d, where is some distance, on the order of a Bohr radius. How do I write p as an operator in that positional basis? I kind of have an idea of how to do it, but I don't want to say anything to bias your answers. I'll hear your ideas then tell you what I did.
 
Physics news on Phys.org
  • #2
Basically I want to write this in operator notation where I have defined the basis states.

[tex]\hat{H} = \frac{1}{2m} \hat{p}_{1}^2 - \frac{1}{4 \pi \epsilon_0} \frac{Z e}{\hat{r}_{1} - R}[/tex]
 
  • #3


In the x basis, the position operator is represented as x, which acts on a wavefunction ψ(x) to give the position of the particle. In the same way, the momentum operator p is represented as p = -iħ(d/dx), which acts on ψ(x) to give the momentum of the particle.

To represent p in the given basis of 0,d,2d, and 3d, we can use the position operator x to define the basis states as |0⟩, |d⟩, |2d⟩, and |3d⟩. Then, we can write p as an operator in this basis as follows:

p = -iħ(d/dx) = -iħ((d/d0)|0⟩ + (d/dd)|d⟩ + (d/d2d)|2d⟩ + (d/d3d)|3d⟩)

= -iħ(0|0⟩ + (1/d)|d⟩ + (2/d)|2d⟩ + (3/d)|3d⟩)

= -iħ(d/d)∑n=0^3 n|nd⟩

where |nd⟩ represents the basis state at position nd.

This representation of p in the given basis shows that the momentum operator is a linear combination of the position basis states, with coefficients proportional to the distances d. This approach can be extended to any discrete basis of points, allowing for the representation of p in different bases for different systems.
 

FAQ: Operator representation of p in x basis.

What is an operator representation of p in x basis?

An operator representation of p in x basis is a mathematical way of representing the momentum operator (p) in terms of the position basis (x). It allows for the calculation of the momentum of a particle in a specific position basis.

How is the operator representation of p in x basis derived?

The operator representation of p in x basis is derived using the principles of quantum mechanics and linear algebra. It involves projecting the momentum operator onto the position basis and expressing it as a linear combination of the position basis vectors.

What is the significance of the operator representation of p in x basis?

The operator representation of p in x basis is significant because it allows for the calculation of the momentum of a particle in a specific position basis, which is an important quantity in quantum mechanics. It also provides a way to relate the momentum and position operators in a mathematical framework.

Can the operator representation of p in x basis be used for any type of particle?

Yes, the operator representation of p in x basis can be used for any type of particle, as long as it follows the principles of quantum mechanics. This includes particles such as electrons, protons, and atoms.

How does the operator representation of p in x basis relate to the Heisenberg uncertainty principle?

The operator representation of p in x basis is related to the Heisenberg uncertainty principle in that it demonstrates the complementary relationship between the position and momentum operators. The uncertainty principle states that the more precisely one knows the position of a particle, the less precisely one can know its momentum, and vice versa. The operator representation of p in x basis shows how these operators are related and how their measurements are subject to uncertainty.

Similar threads

Replies
2
Views
1K
Replies
7
Views
1K
Replies
61
Views
3K
Replies
56
Views
4K
Replies
12
Views
2K
Replies
27
Views
3K
Replies
27
Views
2K
Back
Top