- #1
cse63146
- 452
- 0
Find [tex]\frac{\partial y}{\partial x}[/tex] of [tex]3sin (x^2 + y^2) = 5cos(x^2 - y^2)[/tex]
[tex]\partial y = 6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)[/tex]
[tex]\partial x = 6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)[/tex]
so I thought [tex]\frac{\partial y}{\partial x} = \frac{6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)}{6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)}[/tex]
but instead, the answer is supposed to be:
[tex]\frac{\partial y}{\partial x} = - \frac{6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)}{6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)}[/tex]
[tex]\partial y = 6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)[/tex]
[tex]\partial x = 6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)[/tex]
so I thought [tex]\frac{\partial y}{\partial x} = \frac{6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)}{6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)}[/tex]
but instead, the answer is supposed to be:
[tex]\frac{\partial y}{\partial x} = - \frac{6xcos(x^2 + y^2) + 10xsin(x^2 - y^2)}{6ycos(x^2 + y^2) - 10ysin(x^2 - y^2)}[/tex]