Pendulums, total energy?, and Mathematica

In summary, the Homework Equations state that F=ma, delta K=1/2mv^2, delta U=mgh. The Attempt at a Solution observes that h in the potential equation has got to be equal to L-Lcos(theta), and also that the velocity is going to be equal to L(d(theta/dt)^2, the length multiplied by the rate of change of the center angle. Knowing this, k=1/2 m (L(dtheta/dt))^2, and U= mgh= mg (L-Lcos(theta)) so E= 1/2 m L^2 (dtheta/dt)^2
  • #1
anonindiv
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Homework Statement


A)Show that for a non-frictional, simple linear pendulum (Sin(theta) ~ theta) the total energy of the pendulum (K + U) or kinetic plus potential is given by

E = (1/2) m l^2 (d(theta)/dt)^2 + (1/2) mgl (theta)^2

and therefor E = (1/2) mgl(theta0)^2

theta0 = theta(t=0)


Homework Equations


F=ma , delta K = 1/2mv^2 , delta U = mgh


The Attempt at a Solution



Alright, so I'm essentially lost in this problem, and my last calculus class was approximately 2 years ago.
I understand that the total energy should be the sum of the potential and kinetic energies of the pendulum, so it seems that E = 1/2mv^2 +mgh. But it seems that i am stuck here. I observe that the change between the kinetic energy portion of the equation is different in that v^2 is now l^2 (d(theta)/dt)^2, and the potential mgh now appears as 1/2mgl (theta)^2, but I cannot think of how to determine how to get to that point. And therefor I am unable to get to the main portion of the problem.

{a} One more problem. use mathematica to solve (d(theta)/dt)^2 +g/lsin(theta)=0 . And, show a graph of period vs. (theta 0).

Before this course I have not used mathematica, and now I am facing difficulties. I tried using the dsolve and manipulate functions many times over the past week in an attempt to graph the problem but I have been unsuccessful.

Please note that I am NOT asking for any answers just for guidance.
 

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  • #2
I managed to figure out, after drawing a simple diagram (of course!), that h in the potential equation has got to be equal to L-Lcos(theta). Also, the velocity is going to be equal to L(dtheta/dt), the length multiplied by the rate of change of the center angle. Knowing this,
k= 1/2 m (L(dtheta/dt))^2, and
U= mgh= mg (L-Lcos(theta))
so
E= 1/2 m L^2 (dtheta/dt)^2 + mg(L-Lcos(theta)), which appears to be very similar to the original equation that is given, but I am again stuck. I can't seem to find why the first given equation is equal to the second.
 
  • #3
So... anybody understand how to graph in mathematica or have any words of wisdom on the above problems? Anything would be useful... :D
 

FAQ: Pendulums, total energy?, and Mathematica

What is a pendulum and how does it work?

A pendulum is a weight suspended from a fixed point that is free to swing back and forth under the influence of gravity. The motion of a pendulum is governed by the principle of conservation of energy, where the potential energy at the highest point of the swing is converted into kinetic energy at the lowest point, and vice versa.

How is total energy related to a pendulum's motion?

The total energy of a pendulum is the sum of its kinetic energy and potential energy. As the pendulum swings back and forth, the energy is constantly changing between these two forms. At the highest point of the swing, the potential energy is at its maximum, while at the lowest point, the kinetic energy is at its maximum.

How can Mathematica be used to study pendulums?

Mathematica is a powerful software program that can be used to model and simulate the motion of pendulums. It can calculate the equations of motion, plot the trajectory of the pendulum, and analyze the energy and forces involved.

Can Mathematica be used to find the period of a pendulum?

Yes, Mathematica has built-in functions that can calculate the period of a pendulum based on its length and mass. It can also be used to explore the effects of changing these parameters on the period of the pendulum.

How accurate are the results from using Mathematica to study pendulums?

The accuracy of the results obtained from Mathematica depends on the precision and accuracy of the input values and the complexity of the model. Generally, it is a highly reliable tool for studying pendulums, but it is always important to double check the results and make sure they align with physical laws and principles.

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