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Two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring-loaded gun that is mounted on a table. The target box is 2.20m horizontally from the edge of the table. Bobby compresses the spring 1.10cm, but the center of the marble falls 27.0cm short of the center of the box. How far should Rhonda compress the spring to score a direct hit? Assume that neither the spring nor the ball encounters friction in the gun.
i know i use conservation of energy and X=vt+(1/2)Axt^2 and Y=Voy(t)+(1/2)Ayt^2 and i think you solve for both... but after that i don't know what to do... am i using the right equations? the answer is 1.25cm
i know i use conservation of energy and X=vt+(1/2)Axt^2 and Y=Voy(t)+(1/2)Ayt^2 and i think you solve for both... but after that i don't know what to do... am i using the right equations? the answer is 1.25cm