- #1
Sentin3l
- 118
- 6
Homework Statement
Given a uniform sphere of mass M and radius R. Use integral calculus and start with a mass dm in the sphere. Calculate the work done to bring in the remainder of the mass from infinity. By this technique show that the self-potential energy of the mass is:
[itex] P = -\frac{3}{5} \frac{GM^{2}}{R}[/itex]
Homework Equations
[itex] W = \int\vec{F} \bullet d\vec{r} [/itex]
[itex] F = \frac{GMm}{r^{2}} [/itex]
[itex] F = \frac{GMm}{r^{2}} [/itex]
The Attempt at a Solution
First let me say that this is a cosmology question. I began by considering a differential mass near or at the center of the sphere. Using the above equations for force and work, I derived:
[itex] W = - \int \frac{GM(dm)}{r^{2}} \hat{r} [/itex]
Since the sphere is uniform, it has a constant mass to radius ratio [itex] λ = \frac{M}{R} = \frac{dm}{dr} [/itex]. So using this I found:
[itex] W = -λ\int \frac{GM}{r^{2}}dr = -3λ \frac{GM}{r^{3}} [/itex]
If we substitute [itex] λ = \frac {M}{R} [/itex] and [itex] r=R[/itex], we get the result:
[itex] W = -3 \frac{GM^{2}}{R^{3}}[/itex]
Here is where i think I went wrong, I don't know if I need to deal with [itex]\hat{r}[/itex] and if so, I'm not sure how to approach that.
I think that once I get the work, you use the work-energy theorem, and intial/final KE is 0 so the potential energy equals the work, please correct me if I'm wrong in that.