- #1
Loopas
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I've attached a screenshot of this particular question. I was able to figure out part A but I'm having some difficulty with part B.
Relevant equations:
T = I*alpha
I = .5mr^2 (for a solid cylinder like the grinding wheel)
F = ma
Attempt at solution:
I've gotten as far as setting up the equation and solving for Tf.
(T1-T2)(r) - Tf = (.5)(m)(r)(a)
So Tf = (T1-T2)(r) - (.5)(m)(r)(a)
Which gives me .01878 Nm, which rounds to .019 Nm.
For the acceleration, I've been using .28/6.7 = .04179 m/s^2
Relevant equations:
T = I*alpha
I = .5mr^2 (for a solid cylinder like the grinding wheel)
F = ma
Attempt at solution:
I've gotten as far as setting up the equation and solving for Tf.
(T1-T2)(r) - Tf = (.5)(m)(r)(a)
So Tf = (T1-T2)(r) - (.5)(m)(r)(a)
Which gives me .01878 Nm, which rounds to .019 Nm.
For the acceleration, I've been using .28/6.7 = .04179 m/s^2