Problem with the definition of work

In summary, the definition of work changes depending on the source consulted. For thermodynamics, work is the energy transferred from one system to another. For mechanical work, it is the force applied through a distance. In free gas expansion, work is equal to 0 because there is no resistance. However, the third definition, in contradiction with the first, is that work in this case equals distance * force resisting to the movement.
  • #1
shamanblues
6
0
Hi all,

I m having a little problem with the definition of work:

-Mechanical work is a force applied through a distance, defined mathematically as the line integral of a scalar product of force and displacement vectors. Work is a scalar quantity which can be positive or negative.

-In thermodynamics, thermodynamic work is the quantity of energy transferred from one system to another. It is a generalization of the concept of mechanical work in mechanics.

----->now my real problem comes when i take free gas expansion as an example:normaly work should be equal to 0 (thats what i read in books)
How can that be since we have an expansion DV and obviously a force responsible for that expansion P (pressure).
In my book it says that work in tha case of free expansion equals to 0 because it defines work as:

-distance * force resisting to the movement.

In that case i agree that free gas expansion work equals 0 since there is nothing resisting the expansion, however that third definition is in contradiction with the first one.

I am so confused.Please help!
 
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  • #2
shamanblues said:
Hi all,

I m having a little problem with the definition of work:

-Mechanical work is a force applied through a distance, defined mathematically as the line integral of a scalar product of force and displacement vectors. Work is a scalar quantity which can be positive or negative.

-In thermodynamics, thermodynamic work is the quantity of energy transferred from one system to another. It is a generalization of the concept of mechanical work in mechanics.

----->now my real problem comes when i take free gas expansion as an example:normaly work should be equal to 0 (thats what i read in books)
How can that be since we have an expansion DV and obviously a force responsible for that expansion P (pressure).
No, there is no force or pressure in free expansion. Pressure is is the force (divided by area) of the wall or membrane that prevents free expansion. Remove the barrier and the expansion happens as a consequence of the random motion of the molecules making up the gas.

In my book it says that work in tha case of free expansion equals to 0 because it defines work as:

-distance * force resisting to the movement.

In that case i agree that free gas expansion work equals 0 since there is nothing resisting the expansion, however that third definition is in contradiction with the first one.

I am so confused.Please help!
 
  • #3
indeed..! now i understand better.
one more question however:

What should i learn:
-work=force*distance (my last year book) or
-work=distance*force resisting to the movement (this years book..)

...or is it quantitatively (EXACTLY (?)) the same since if there is little resistance, distance will be longer and if the resistance is greater, distance will be shorter for the same force applied?
 
Last edited:
  • #4
shamanblues said:
What should i learn:
-work=force*distance (my last year book) or
-work=distance*force resisting to the movement (this years book..)

...or is it quantitatively (EXACTLY (?)) the same since if there is little resistance, distance will be longer and if the reistance is greater, diastance will be shorter for the same force applied?

To be fair, they are the same, just probably not explained to you in properly. The one you want to learn is the second one because unless you are in a vaccuum, there will always be a resistive force (normally in the opposite direction to motion).

The Bob (2004 ©
 
  • #5
You have to consider the work done by the expanding gas. So if the gas expands by applying a force against something, say a piston, energy is removed from the gas in doing work on another system.
 
  • #6
As long as an object is not accelerating, the net force is 0 so the "resistive force" is the same as the force applied to the object.
If the object is accelerating, then the work done by the force goes part into overcoming the resistive force and part into increasing the kinetic energy.
 
  • #7
All of your replies were so helpful !
Thank you! I understand better now.

(could you please get all together and write a book!
Seriously, i got more out of your 4 posts than i did reading my whole thermodynamics chapter...)
 

FAQ: Problem with the definition of work

What is the definition of work?

The definition of work can vary depending on the context and field of study. Generally, it is defined as the application of force to an object over a distance, resulting in the displacement of the object. However, this definition may not encompass all aspects of work, and there may be different interpretations and nuances within different scientific disciplines.

What are the different types of work?

There are several different types of work, including mechanical work, electrical work, and thermodynamic work. Mechanical work involves the displacement of an object due to a force, electrical work involves the movement of charged particles, and thermodynamic work involves the transfer of energy due to a change in temperature or pressure.

What are the limitations of the definition of work?

The definition of work has some limitations, such as not taking into account the direction of the force or the time it takes to complete the work. Additionally, it may not accurately describe work in certain circumstances, such as in situations where the force is not constant or when there is no displacement of the object.

How is work related to energy?

Work and energy are closely related concepts. The work done on an object is equal to the change in its energy. This is seen in the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy.

Why is the definition of work important in science?

The definition of work is important in science because it allows us to quantify and understand the effects of forces on objects and their energy. It is a fundamental concept in physics and is used in various fields, including mechanics, thermodynamics, and electromagnetism.

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