- #1
Miike012
- 1,009
- 0
Hello,
1. Proof: Let denote the number of representations of to the base . We must show that always equals 1.
(this means that we are trying to prove that there is only one representation?)
Line 2. Suppose that
[tex] n = a_{0}k^{s} + a_{1}k^{s-1} + ... + a_{s-t}k^{t} [/tex]
then...
Line 3. [tex] n - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + a_{s-t}k^{t} - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + \left(a_{s-t} - 1\right)k^{t} + k^{t} - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + \left(a_{s-t} - 1\right)k^{t} + \sum_{j=0}^{t-1} \left(k - 1\right)k^{t}[/tex]
(I am not understanding the proof. How did line 2 get to line 3 algebraically?)
I am only in algebra right now... when will I learn how to read a proof and understand it?
Is there anything on the internet that someone can recommend reading so I will have a better understanding ?
Thanky you.
1. Proof: Let denote the number of representations of to the base . We must show that always equals 1.
(this means that we are trying to prove that there is only one representation?)
Line 2. Suppose that
[tex] n = a_{0}k^{s} + a_{1}k^{s-1} + ... + a_{s-t}k^{t} [/tex]
then...
Line 3. [tex] n - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + a_{s-t}k^{t} - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + \left(a_{s-t} - 1\right)k^{t} + k^{t} - 1 = a_{0}k^{s} + a_{1}k^{s-1} + ... + \left(a_{s-t} - 1\right)k^{t} + \sum_{j=0}^{t-1} \left(k - 1\right)k^{t}[/tex]
(I am not understanding the proof. How did line 2 get to line 3 algebraically?)
I am only in algebra right now... when will I learn how to read a proof and understand it?
Is there anything on the internet that someone can recommend reading so I will have a better understanding ?
Thanky you.