Proving inf(x_n)=1 for x_{n+1}=2-\frac{1}{x_n}

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In summary, the conversation is about trying to show that the limit of x_n as n approaches infinity is equal to 1, given the equation x_{n+1}=2-\frac{1}{x_n}. The person asking for help is struggling with the notation and has been given a hint to subtract 1 from both sides.
  • #1
hockey777
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x_{n+1}=2-\frac{1}{x_n}

I need to show that inf(x_n)=1

For someone reason this is proving to be more difficult than I thought, could someone pleas help?
 
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  • #2
It would be a little clearer if you defined x_0. Also your notation is a little strange - frac{1}{x} means what? I am guessing it means the fractional part, but I am not sure.
 
  • #3
Welcome to PF!

hockey777 said:
[tex]x_{n+1}=2-\frac{1}{x_n}[/tex]

I need to show that inf(x_n)=1

Hi hockey777! Welcome to PF! :smile:

Hint: start by subtracting 1 from each side. :wink:

(and type [noparse][tex] before and [/tex] after your equations![/noparse] :smile:)
 

FAQ: Proving inf(x_n)=1 for x_{n+1}=2-\frac{1}{x_n}

What is meant by the term "Proving Infinum of Set x_n=1"?

The term "Proving Infinum of Set x_n=1" refers to the process of proving that the set of numbers, represented by x_n=1, has an infimum or the smallest possible value.

Why is it important to prove the infinum of a set?

Proving the infinum of a set is important because it provides a clear understanding of the lower bound or smallest value of the set. This information is useful in various mathematical calculations and proofs.

What is the mathematical notation for representing the infinum of a set?

The infinum of a set is represented by the symbol "inf" followed by the set within brackets, such as inf{x_n=1}.

How can one go about proving the infinum of a set?

The most common approach to proving the infinum of a set is by using the definition of infinum, which states that the infinum of a set is the greatest lower bound of the set. This can be proven by showing that the infinum is less than or equal to all elements in the set, and any number greater than the infinum cannot be a lower bound of the set.

Can the infinum of a set x_n=1 be equal to any other number in the set?

No, the infinum of a set x_n=1 is the smallest possible value and cannot be equal to any other number in the set. It is either less than or equal to all elements in the set, but not equal to any of them.

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