- #1
Frankenstein19
- 56
- 0
Ok so when differentiating
1/(1-x)= Σ xn from n=0 to infinity
the book says it is 1/(1-x)^2 = Σ n*(x)n-1 from n=1 to infinity
i don't understand why the original sum starts at 0 and then the derived sum starts at 1
1/(1-x)= Σ xn from n=0 to infinity
the book says it is 1/(1-x)^2 = Σ n*(x)n-1 from n=1 to infinity
i don't understand why the original sum starts at 0 and then the derived sum starts at 1