- #1
yungman
- 5,755
- 293
Why
[tex] \int_a^b \nabla T\; d\vec l \;=\; T(b)-T(a)[/tex]
Why integration of a gradient is always path independent?
[tex] \int_a^b \nabla T\; d\vec l \;=\; T(b)-T(a)[/tex]
Why integration of a gradient is always path independent?