Question Regarding Velocity-Time Graphs

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The first one is a straight line with slope 2, the second one is a straight line with slope 1/2, and the third one is a parabola (open upwards) that intersects with the other two lines at t = 0 and t = 4.
  • #1
Drewski
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Homework Statement



The figure below shows the velocity-time graph of a train that starts from the origin at t = 0s

5d714o.jpg


a) Draw a position-time graph and an acceleration-time graph for the train

b) Find the acceleration of the train at t = 3.0 s

Homework Equations



a = Vf - Vi / t

x = 1/2 at^2 + Vi x t + Xi


The Attempt at a Solution



a)
xfq3w6.jpg


b) 1 m/s^2

Do my answers look right? If not, what did I do wrong?
 
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  • #2
The acceleration is correct, and the graph of x(t) is almost correct, only the part between 0 and 4 s does not look parabolic, and check x at t=2 s. ehild
 
  • #3
Looks right to me. But those are really, really, truly, bad graphs.
 

FAQ: Question Regarding Velocity-Time Graphs

What is a velocity-time graph?

A velocity-time graph is a visual representation of the relationship between an object's velocity and time. It shows how an object's velocity changes over a certain period of time.

How do you interpret a velocity-time graph?

The slope of a velocity-time graph represents the object's acceleration. A steeper slope indicates a higher acceleration. The area under the curve represents the object's displacement.

What does a horizontal line on a velocity-time graph signify?

A horizontal line on a velocity-time graph means that the object's velocity is constant, and there is no acceleration. This could indicate that the object is at rest or moving at a constant speed.

How does a positive and negative slope differ on a velocity-time graph?

A positive slope on a velocity-time graph indicates that the object is accelerating in the positive direction. A negative slope means that the object is accelerating in the negative direction or decelerating.

How can you determine an object's displacement from a velocity-time graph?

The displacement can be determined by finding the area under the curve on a velocity-time graph. This can be done by dividing the graph into smaller, known shapes (e.g. rectangles or triangles) and calculating their individual areas.

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