Real Analysis: Prove that the interval [0,1] is not a zero set

In summary, a zero set is a set that can be covered by a union of open intervals with arbitrarily small total length. The set of rational numbers in [0,1] can be covered in such a way, but the set of all real numbers in [0,1] cannot, making it not a zero set. The definition of a zero set can vary depending on context, but in this case it refers to a subset of R with a (Lebesgue) measure of zero.
  • #1
datenshinoai
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Homework Statement



Prove that the interval [0,1] is not a zero set.

2. The attempt at a solution

Assume for contradiction that the interval [0,1] = Z is a zero set. This mean that given epsilon greater than 0, there is a countable coverage of Z by open intervals (ai, bi) (___I don't know what those intervals should be...___) such that the summation of bi - ai is less than epsilon.

But since Z is uncountable, there cannot be a countable coverable of Z by open intervals. Thus Z is not a zero set.
 
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  • #2
Unfortunately that's not very convincing. So what if Z is uncountable? It can still be covered by countably many open intervals. (And in fact there are uncountable zero sets. Can you think of one?) The point is that it can't be covered by countably many intervals whose total length is small -- after all, the length of [0,1] is 1!
 
  • #3
Perhaps my question really is, what is the definition of a zero set? The book doesn't have a clear definition.
 
  • #4
The particulars depend on context. Usually, a zero set is the set of solutions to an equation f(x)=0. But the definition can vary, by restricting which kinds of functions you can use, whether the this criterion is applied locally or globally, and other various things. Surely your book gives an explicit definition somewhere?
 
  • #5
Hurkyl said:
The particulars depend on context. Usually, a zero set is the set of solutions to an equation f(x)=0. But the definition can vary, by restricting which kinds of functions you can use, whether the this criterion is applied locally or globally, and other various things. Surely your book gives an explicit definition somewhere?
I think in this case a zero set means a subset of R of (Lebesgue) measure zero.

datenshinoai, think of this in terms of 'length.' A zero set has zero 'length.' To be precise, a set is a zero set iff you can cover it with countably many intervals of arbitrarily small total length. (At least this is what your definition appears to be.)
 
  • #6
datenshinoai said:
Perhaps my question really is, what is the definition of a zero set? The book doesn't have a clear definition.

You gave the definition of a zero set in your problem statement. It's a set that can be covered by a union of open intervals with arbitrarily small total length. The set of rational numbers in [0,1] can be covered in such a way. Why not the set of all REAL numbers in [0,1]?
 

FAQ: Real Analysis: Prove that the interval [0,1] is not a zero set

Why is it important to prove that the interval [0,1] is not a zero set in Real Analysis?

In Real Analysis, a zero set is a set of points where a given function takes on the value of zero. Proving that the interval [0,1] is not a zero set is important because it helps to establish the properties and limitations of functions on that interval. This proof can also be used to disprove certain hypotheses or conjectures in Real Analysis.

How is the interval [0,1] defined in Real Analysis?

In Real Analysis, the interval [0,1] is defined as the set of all real numbers between 0 and 1, including both 0 and 1. This interval is commonly used in Real Analysis as it represents a closed and bounded set, allowing for more precise analysis and calculations.

What is the definition of a zero set in Real Analysis?

In Real Analysis, a zero set is a set of points where a given function takes on the value of zero. In other words, a zero set is the set of all values of x for which f(x) = 0. It is important to note that not all functions have a zero set, and proving that a set is not a zero set helps to establish the properties and limitations of that function.

How is the proof that the interval [0,1] is not a zero set typically approached in Real Analysis?

The proof that the interval [0,1] is not a zero set in Real Analysis is typically approached by contradiction. This means assuming that the interval is indeed a zero set and then showing that this assumption leads to a contradiction. This contradiction proves that our initial assumption was incorrect, and therefore, the interval [0,1] is not a zero set.

Can the proof that the interval [0,1] is not a zero set be generalized to other intervals?

Yes, the proof that the interval [0,1] is not a zero set can be generalized to other intervals as well. The same approach of contradiction can be used to prove that any closed and bounded interval in Real Analysis is not a zero set. This is because all closed and bounded intervals have a finite range of values, making it impossible for the function to take on the value of zero for all points in the interval.

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