- #1
murmillo
- 118
- 0
Homework Statement
There's something about the Riemannian metric that I don't understand. I don't understand the compatibility with the metric. If X,Y,Z are vector fields, the Riemannian connection (I'll call it D) satisfies DX(g(Y,Z)) = g(DXY,Z) + g(Y, DXZ), where g is the Riemannian metric. But g(Y,Z) is a scalar, so how does DXg(Y,Z) make sense?